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2 years ago

ILL GIVE EVERYTHING IF U GET IT RIGHTTT pwease>>?

Mathematics

2 answers:

Ierofanga [76]2 years ago

8 0

Answer:

7 but i am so sorry if this is wrong because i did not know what they started out with

Step-by-step explanation:

Viktor [21]2 years ago

3 0

Answer:

-4

Step-by-step explanation:

you have to do -11+7

hope this helps dont 4get to like and star

-mercury

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Six times a number, increased by 3 is is 27. find the number

Mekhanik [1.2K]

Answer : The number is 4.

Step-by-step explanation:

Given : 

six times a number, increased by 3 is is 27.

To Find: 

The number.

Solution : 

Let the number is x

six times a number is 6x

Increased by 3 = 6x+3

According to the given question :

Solving the value x : 

6x+3 =27

6x = 27-3

6x = 24

x = 24/6

x = 4

Hence, the number is 4.

6 0

3 years ago

What is one-fourth of 24

aev [14]

Answer:

Step-by-step explanation:

One fourth is ÷4

24÷4=6

8 0

2 years ago

Read 2 more answers

Please answer this!!

Vinvika [58]

Answer:

Step-by-step explanation:

if angle c is 45 then angle A is 45 also

Hence AB is equal to BC

8 0

3 years ago

Solve each inequality, and then drag the correct solution graph to the inequality.

Nesterboy [21]

The correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

$4(9x-18)>3(8x+12)$

First, clear the brackets,

$36x-72>24x+36$

Then, collect like terms

$36x-24x>36+72\\12x >108$

Now divide both sides by 12

$\frac{12x}{12} > \frac{108}{12}$

∴ $x > 9$

For the second inequality

$-\frac{1}{3}(12x+6) \geq -2x +14$

First, clear the fraction by multiplying both sides by 3

$3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)$

$-1(12x+6) \geq -6x +42$

Now, open the bracket

$-12x-6 \geq -6x +42$

Collect like terms

$-6 -42\geq -6x +12x$

$-48\geq 6x$

Divide both sides by 6

$\frac{-48}{6} \geq \frac{6x}{6}$

$-8\geq x$

∴ $x\leq -8$

For the third inequality,

$1.6(x+8)\geq 38.4$

First, clear the brackets

$1.6x + 12.8\geq 38.4$

Collect likes terms

$1.6x \geq 38.4-12.8$

$1.6x \geq 25.6$

Divide both sides by 1.6

$\frac{1.6x}{1.6}\geq \frac{25.6}{1.6}$

∴ $x \geq 16$

Let the graphs be A, B and C from left to right

The first graph (A) shows $x\leq -8$ and this matches the 2nd inequality

The second graph (B) shows $x \geq 16$ and this matches the 3rd inequality

The third graph (C) shows $x > 9$ and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

Learn more here: brainly.com/question/17448505

8 0

2 years ago

Neeeeeeeeeeeeeedddddddddddddddddddd will give brain

Igoryamba

Answer:

Step-by-step explanation:

11 times 7 =77

6 0

3 years ago