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2 years ago

Could someone help me out?

Mathematics

1 answer:

CaHeK987 [17]2 years ago

6 0

<h3>The required value of $\lim_{h \to0 \zero} 46x^11+32xh^3+6x^15h+23$ is $46x^11+23$

What is limit?</h3>

Limit, can be defined as the every nearby the value of a variable for a function exists, is called limits|

⇒ $\lim_{h \to0 \zero} 46x^11+32xh^3+6x^15h+23$

When putting h = 0

⇒ $46x^11+23$

Thus, the value of a function of its limit is given by $46x^11+23$

Learn more about limits here:
brainly.com/question/18008819

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Someone please help me with this question 8.62 – (0.25 x 4.1)

Contact [7]

Answer:

7.595

Step-by-step explanation:

Use PEMDAS

So if we know we need to use the parenthesis first since P stands for parenthesis

So solve (0.25 x 4.1) first.

(0.25 x 4.1) =1.025

We know that (0.25 x 4.1) =1.025 so we plug in 8.62-1.025

When subtracted we get the answer of 7.595

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X^4-x^2-42=0 <br>need to solve equation and find solution set

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We factor,

$(x^2 - 7)(x^2+6) = 0$

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3 years ago

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City planners are planning to build a new community park. They agree that the park will be rectangular in shape, but the propose

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Answer:

Step-by-step explanation:

The area of the rectangular park will be the product of its length and width. This relation is used to write an equation to find the original width of the park.

<h3>Width</h3>

Let w represent the original width of the park in meters. The new width is 4.7 meters more, so is represented by (w +4.7).

<h3>Other dimensions</h3>

The length of the park is given as 21.6 meters. The area is given as 714.96 square meters.

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The various dimensions of the park are related by the area formula:

A = LW

714.96 = 21.6(w +4.7)

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