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BabaBlast [244]
3 years ago
7

A line contains the point (8, –5). If the slope of the line is 5/7, write the equation of the line using point-slope form.

Mathematics
2 answers:
IgorLugansk [536]3 years ago
7 0

Answer: (y+5)=\frac{5}{7}(x-8)

Step-by-step explanation:

The point slope form of a line having slope m and point (a,b) is given by :-

(y-b)=m(x-a)

Given: A line contains the point = (8, –5)

The slope of the line =\frac{5}{7}

Now, the point slope form of a line having slope \frac{5}{7} and point (8,-5) is given by :-

(y-(-5))=\frac{5}{7}(x-8)\\\\\Rightarrow\ (y+5)=\frac{5}{7}(x-8)

Hence, the equation of the line =(y+5)=\frac{5}{7}(x-8)

dezoksy [38]3 years ago
4 0

Answer:  The required equation of the line is y+5=\dfrac{5}{7}(x-8).

Step-by-step explanation:  Given that a line contains the point (8, -5) and the slope of the line is {tex]\dfrac{5}{7}.[/tex]

We are to write the equation of the line using point-slope form.

We know that

the equation of a line with slope m and passing through the point (a, b) is given by

y-b=m(x-a).

For the given line, we have

m=\dfrac{5}{7},~~~(a,b)=(8,-5).

Therefore, the equation of the line will be

y-b=m(x-a)\\\\\Rightarrow y-(-5)=\dfrac{5}{7}(x-8)\\\\\Rightarrow y+5=\dfrac{5}{7}(x-8).

Thus, the required equation of the line is y+5=\dfrac{5}{7}(x-8).

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