The question is incomplete. Here is the complete question:
Mr.yueng graded his students math quizzes students came up with four different answers when solving the equation x3=22. Which answers is correct.
(A) 
(B) ![\sqrt[3]{22}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B22%7D%20)
(C)
(D) 
Answer:
(B) ![\sqrt[3]{22}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B22%7D)
Step-by-step explanation:
Given:
The equation to solve is given as:

Here, the left hand side of the equation has a variable 'x' in exponent form. So, in order to solve for 'x', we have to eliminate the exponent.
For removing the exponent, we have to take cubic root on both the sides. As we know that,
![\sqrt[n]{x^n} =x](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5En%7D%20%3Dx)
So, taking cubic root on both the sides, we get
![\sqrt[3]{x^3}=\sqrt[3]{22}\\\\x=\sqrt[3]{22}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%3D%5Csqrt%5B3%5D%7B22%7D%5C%5C%5C%5Cx%3D%5Csqrt%5B3%5D%7B22%7D)
Therefore, the second student has written the correct answer and hence the correct option is (B).
Answer:
$0.30 + $0.03n > $0.02 + $0.02n
Step-by-step explanation:
company x = $0.30 + $0.03n
company y = $0.02 + $0.02n
$0.30 + $0.03n > $0.02 + $0.02n
10 students per gender:
Boys: <span>four Xs over five and one X over zero, two, three, four, ten, and twelve.
5, 5, 5, 5, 0, 2, 3, 4, 10, 12 </span>→ 0, 2, 3, 4, 5, 5, 5, 5, 10, 12<span>
mean: 5.1
range: 12
</span><span>Girls: three Xs above eight, two Xs above three and four, and one X above two, six and seven.
8, 8, 8, 3, 3, 4, 4, 2, 6, 7 </span>→ 2, 3, 3, 4, 4, 6, 7, 8, 8, 8
<span>mean: 5.3
range: 6
The boys have the higher range while the girls have the higher mean value.
</span><span>
</span>
C) 18 because you could get 6 numbers with red, 6 numbers with brown and 6 numbers with yellow.
Answer:
C. y-5>3x-7
Step-by-step explanation:
If you multiply y and x to 0 you get -5 > -7