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Ugo [173]
2 years ago
12

Use a truth table to decide whether each argument is valid or invalid If a person is on this reality show, they must be self-abs

orbed. Laura is notself-absorbed. Therefore, Laura cannot be on this reality show.
Mathematics
1 answer:
bezimeni [28]2 years ago
4 0

The arguments are valid therefore F  F →T

<h3>What is a truth table?</h3>

A truth table is a mathematical table which shows the truth values for a given set of arguments and tells if the argument is valid or invalid.

Analysis:

Argument 1( P)= if a person is on this reality show(true) T

Argument 2(Q) = the person is self absorbed true(T)

Laura is not self absorbed = False(≈Q)

Laura wont be on the reality show = False(≈P)

So she can only be on the reality show if she is self absorbed else she cannot.

so F F → T

Which means that the argument is valid.

Learn more about Truth tables: brainly.com/question/14458200

#SPJ1

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2 inches per hour, 5 inches, y=2x+5

Step-by-step explanation:

No, I don't think I will

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From an airplane flying over the ocean, the angle of depression to a submarine lying under the surface if 24 degrees 10 minutes.
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I think is 10 m/ s per sec
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Find the slope of the line passing through the points (-6,2), (0,-6).A 6B 2.C-4/3DOE-3/1
NNADVOKAT [17]

Given data:

The first point given iis (a, b)=(-6,2).

The second point given is (c,d)=(0, -6).

The expression for the slope is,

m=(d-b)/(c-a)

Substitute the given points in the above expression.

m=(-6-2)/(0-(-6))

=(-8)/(6)

=-4/3

Thus, the slope of the line is -4/3, so (C) option is correct.

8 0
1 year ago
B. Hanapin ang sagot (quotient) gamit ang paghahati-hati. (1 puntos bawat bilang = 5 puntos) 26.4)448 27.800 + 10 = 1 28. 3)663
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3 years ago
In physics, if a moving object has a starting position at so, an initial velocity of vo, and a constant acceleration a, the
emmasim [6.3K]

Answer:

a=\frac{2S -2v_ot-2s_o}{t^2}

Step-by-step explanation:

We have the equation of the position of the object

S = \frac{1}{2}at ^2 + v_ot+s_o

We need to solve the equation for the variable a

S = \frac{1}{2}at ^2 + v_ot+s_o

Subtract s_0 and v_0t on both sides of the equality

S -v_ot-s_o = \frac{1}{2}at ^2 + v_ot+s_o - v_ot- s_o

S -v_ot-s_o = \frac{1}{2}at ^2

multiply by 2 on both sides of equality

2S -2v_ot-2s_o = 2*\frac{1}{2}at ^2

2S -2v_ot-2s_o =at ^2

Divide between t ^ 2 on both sides of the equation

\frac{2S -2v_ot-2s_o}{t^2} =a\frac{t^2}{t^2}

Finally

a=\frac{2S -2v_ot-2s_o}{t^2}

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