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andrey2020 [161]

3 years ago

6

Estimate area pls i

1 answer:

NNADVOKAT [17]3 years ago

3 0

Answer:

The simplest (and most commonly used) area calculations are for squares and rectangles. To find the area of a rectangle, multiply its height by its width. For a square you only need to find the length of one of the sides (as each side is the same length) and then multiply this by itself to find the area.

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Two of the most popular options on a certain type of new car are automatic transmission and built-in GPS. Suppose that 90% of al

padilas [110]

Answer:

0.95 = 95% probability that the next person to purchase this car will request at least one of automatic transmission or built-in GPS

Step-by-step explanation:

We solve this question treating these probabilities as Venn sets.

I am going to say that:

Event A: Requesting automatic transmission

Event B: Requesting built-in GPS

90% of all buyers request automatic transmission

This means that $P(A) = 0.9$

82% of all buyers request built-in GPS

This means that $P(B) = 0.82$

77% of all buyers request both automatic transmission and built-in GPS.

This means that $P(A \cap B) = 0.77$

What is the probability that the next person to purchase this car will request at least one of automatic transmission or built-in GPS

This is $P(A \cup B)$ , which is given by:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

So

$P(A \cup B) = 0.9 + 0.82 - 0.77 = 0.95$

0.95 = 95% probability that the next person to purchase this car will request at least one of automatic transmission or built-in GPS

3 0

3 years ago

You might need:

ELEN [110]

Answer:

15

Step-by-step explanation:

15 pages can henry white in 8 hours

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4 years ago

What is the area of a triangle with vertices at (−4, 1) , (−7, 5) , and (0, 1) ? Enter your answer in the box. ___units²

AnnZ [28]

Check the picture below.

you can pretty much count those lengths off the grid.

recall that A = 1/2 bh.

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Answer:

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Step-by-step explanation:

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amm1812

Can be achieved by dividing.
___
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Therefore the answer is B

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4 years ago

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