Let
x--------------> a number
we know that
<span>three sets of a sum of a number and four----------> 3(x+4)
t</span><span>he sum of 7 times the same number and 13--------> 7x+13
therefore
</span>(Three sets of a sum of a number and four) are added (to the sum of 7 times the same number and 13) ----------> [3(x+4)] + [7x+3]
[3(x+4)] + [7x+3]------> [3x+12] + [7x+3]=10x+15
the answer is 10x+15
The answer choice that is false is D.
The form of the y-intercept is (0,Y). Remember that x comes first in an ordered pair and y comes second.
Hope this helps!
Answer:
(x+1)(x-3i) (x+3i)
Step-by-step explanation:
x^3 + x^2 + 9x+9
We will use factor by grouping
Factor out x^2 from the first group and 9 from the second group
x^3 + x^2 + 9x+9
x^2( x+1) + 9(x+1)
Factor out (x+1)
(x+1) ((x^2+9)
Now factor x^2+9
x^2 -(3i)^2 = (x-3i) (x+3i)
Replacing this
(x+1)(x-3i) (x+3i)
answer;
x=0
Step-by-step explanation:
4 + 2 (x + 3x) = 4 - x(2-3) + 2x
let remove d brackets
4 + 2x + 6x = 4 - 2x + 3x + 2x
llet collect like terms
2x + 6x - 3x -2x + 2x = 4-4
5x = 0
x = 0
