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Stells [14]
3 years ago
15

HELP ASAP PLEASE & SHOW UR WORK!! THANK YOU <333

Mathematics
1 answer:
alekssr [168]3 years ago
4 0

Answer:

              \bold{x_1=-\dfrac{3+\sqrt{41}}{2}\approx-4.7\ ,\quad x_2=-\dfrac{3-\sqrt{41}}{2}\approx1.7}

Step-by-step explanation:

-2x^2-3x+4=0\\\\a=-2\,,\ b=-3\,,\ c=4\\\\\\x=\dfrac{-b-\sqrt{b^2\pm4ac}}{2a}=\dfrac{-(-3)\pm\sqrt{(-3)^2-4(-2)(4)}}{2(-1)}=\dfrac{3\pm\sqrt{9+32}}{-2}\\\\\\x_1=-\dfrac{3+\sqrt{41}}{2}\approx-4.7\ ,\qquad x_2=-\dfrac{3-\sqrt{41}}{2}\approx1.7

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If sin(y°) = cos(x°), which of the following statements is true?
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Answer:

<u>y = w and ΔABC ~ ΔCDE</u>

Step-by-step explanation:

Given sin(y°) = cos(x°)

So, ∠y + ∠x = 90°  ⇒(1)

And as shown at the graph:

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From (1) and (2)

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Answer:

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Step-by-step explanation:

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