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tamaranim1 [39]
2 years ago
9

What is the area of this trapezoid?

Mathematics
1 answer:
Alexandra [31]2 years ago
3 0

Answer:

440cm²

Step-by-step explanation:

*Area= (a+b)/2×h

(19+25)/2*20

= _ * 440cm². *_

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What is the solution to the system of equations? y = A system of equations. Y equals StartFraction 2 over 3 EndFraction x plus 3
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Answer:

The solution to the given system of equations is (-2,\frac{5}{3})

Therefore the values of x and y are x=-2 and y=\frac{5}{3}

Step-by-step explanation:

Given equations can be written as

y=\frac{2}{3}x+3\hfill (1)

x=-2x+3x=-2\hfill (2)

Solving equation(2) we get

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Substitute x=-2 in equation (1) we get

y=\frac{2}{3}(-2)+3

=-\frac{4}{3}+3

=\frac{-4+9}{3}

=\frac{5}{3}

Therefore the values of x and y are  x=-2 and y=\frac{5}{3}

The solution to the given system of equations is (-2,\frac{5}{3})

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Answer:

6.04 inches.

Step-by-step explanation:

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Divide 604 with 100:

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The height of Corbin's model would thereby be 6.04 inches.

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In 22, you're looking for the vertical height of the triangle. You're given the angle opposite the side you want to find (which I'll call x) and the length of the hypotenuse. This sets you up with the relation

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\sin\theta=\dfrac{1500}{5000}=\dfrac3{10}\implies\theta=\arcsin\dfrac3{10}\approx17.46^\circ
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