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GenaCL600 [577]
3 years ago
9

Que es 9+10 A.) 45 B.) 19 C.) 21 D.) 24

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
6 0

Answer:

b

Step-by-step explanation:10+9=19 so thats why its b

Vlad [161]3 years ago
5 0
Answer is B. 19! 9+10=19
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Use properties of equality to find the value of x in the equation 12(5x-4.5)=36
lukranit [14]

Answer:

x= 1.5 Hope that helps!

Step-by-step explanation:

1. 12(5x-4.5)=36 First Divide both by 12 5x-4.5-36/12 = 3

2. 5x-4.5=3 add 4.5 to both sides

3. 5x= 3+4.5 = 7.5

4. 5x=7.5 divide both sides by 5 x=7.5/5= x=1.5

So, x=1.5 would be your answer. Can you make me Brainliest Please  

4 0
3 years ago
10z + 3 =9z solve for z
Eva8 [605]

z=-3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Peter sells 10 wallets in 2 days. After 40 days how many wallets should be sold?
liubo4ka [24]

Answer:

200 Wallets

Step-by-step explanation:

If he sells ten in two days, let's just say he sells 5 a day. If you do the math, 40 days×5 wallets, you get 200.

4 0
4 years ago
4 is what percent of 550
vladimir2022 [97]
If you want to evaluate what percent of 550 is 4, you can do this in two following steps.<span>
<span>First, you have to write it as a fraction: 4</span>/550.
Second, you have to transform this fraction to percent: (4/550)*100%.

(4/550)*100% = 0.0072727272727273*100% = 0.727%

<span>The correct result is </span>0.727%.</span>
6 0
3 years ago
Two sisters, sister A and sister B, play SCRABBLE with each other every evening. Sister A is a statistician, and she draws a ran
snow_tiger [21]

Answer:

First question: LCL = 522, UCL = 1000.5

Second question: A sample size no smaller than 418 is needed.

Step-by-step explanation:

First question:

Lower bound:

0.36 of 1450. So

0.36*1450 = 522

Upper bound:

0.69 of 1450. So

0.69*1450 = 1000.5

LCL = 522, UCL = 1000.5

Second question:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

The project manager believes that p will turn out to be approximately 0.11.

This means that \pi = 0.11

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The project manager wants to estimate the proportion to within 0.03

This means that the sample size needed is given by n, and n is found when M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.11*0.89}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.11*0.89}

\sqrt{n} = \frac{1.96\sqrt{0.11*0.89}}{0.03}

(\sqrt{n})^2 = (\frac{1.96\sqrt{0.11*0.89}}{0.03})^2

n = 417.9

Rounding up

A sample size no smaller than 418 is needed.

6 0
3 years ago
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