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Rainbow [258]
1 year ago
15

A motivation for scientific management, which uses time and motion studies and work standardizations, is to:

Business
1 answer:
bulgar [2K]1 year ago
7 0

Make manual labor work more efficiently.

Scientific management

This is an art of knowing accurately that "what is to be done" and "how it's to be done". There are some of the studies:

MOTION STUDY- This is the study which helps to reduce unwanted movements so that it would take very less time to perform the job effectively.

TIME STUDY- This helps in setting the standard time for performing the particular task more efficiently. It is to be set according the task given.

WORK STANDARDIZATION- It is the type of a process in which standards are set for every business activity- raw materials, product, time, methods or working conditions.

Hence, these are all studies which helps to make "manual labor work more efficiently".

Learn more about this here-

brainly.com/question/13191706

#SPJ4

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In a relationalâ database, the three basic operations used to develop useful sets of dataâ are:
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E is the correct answer
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"Dubas Co. is a U.S.-based MNC that has a subsidiary in Germany and another subsidiary in Austria. Both subsidiaries frequently
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Answer:

$525,000

Explanation:

The computation of the net inflow or outflow is shown below:

= Total outflow - total inflow

where,

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Now put these values to the above formula  

So, the value would equal to

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3 0
3 years ago
How do marginal costs<br> and benefits relate to trade-offs?
Lisa [10]

Answer:

A trade-off is the actual alternative option that is given up, while the value of this alternative option is the opportunity cost. ... Marginal cost is the cost of using one more unit of a good or service, and marginal benefit is the benefit or satisfaction received from using one more unit of a good or service.

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6 0
3 years ago
You just sold 900 shares of Alcove stock at a price of $34.08 a share. Last year you paid $39.20 a share to buy this stock. You
ehidna [41]

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d. -$4,608

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5 0
3 years ago
Write the AddressList method newBusiness. This method searches addresses for an existing business with an identical address (i.e
max2010maxim [7]

Answer:

See explaination

Explanation:

// Address.java

public class Address {

/**

* The name of the business

*/

private String name;

/**

* The name of the street the business is on

*/

private String street;

/**

* The street number of the business

*/

private int number;

/**

* Constructs an Address that represents a business with name nm,

* at number no on the street st

*/

public Address(String nm, String st, int no)

{

name = nm;

street = st;

number = no;

}

/**

* Returns the name of the business

*/

public String getName()

{

return name;

}

/**

* Returns the name of the street on which the business is located

*/

public String getStreet()

{

return street;

}

/**

* Returns the street number of the business

*/

public int getNumber()

{

return number;

}

}

//end of Address.java

//AddressBook.java

import java.util.ArrayList;

import java.util.List;

public class AddressBook {

/**

* The list of business addresses. No two businesses in the list

* can have the same address (both the same street and street number)

*/

private List<Address> addresses;

/**

* Constructs an empty AddressBook

*/

public AddressBook()

{

addresses = new ArrayList<Address>();

}

/**

* atparam st the name of a street

* atreturn a list with the names of each business with an address on that street

*/

public List<String> onStreet(String st)

{

// create an empty output list of names of business

List<String> businessName = new ArrayList<String>();

// loop over the list of addresses

for(int i=0;i<addresses.size();i++)

{

// if ith street of address = nm, add the name of the business to the output list

if(addresses.get(i).getStreet().equalsIgnoreCase(st))

businessName.add(addresses.get(i).getName());

}

return businessName; // return the list

}

/**

* Searches for an existing business with an identical address (street and number

* both match). Updates the record to an address with name nm, street st and number no.

* If no entry already exists adds a new address to the end of the list with these parameters.

*

* atparam nm the name of the business

* atparam st the street the business is on

* atparam no the street number of the business

* atreturn the index of where the business address is on the list

*/

public int newBusiness(String nm, String st, int no)

{

// loop over the list of addresses

for(int i=0;i<addresses.size();i++)

{

// if ith index addresses match the street and number of the input st and no

if((addresses.get(i).getStreet().equalsIgnoreCase(st)) && (addresses.get(i).getNumber() == no))

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addresses.remove(i); // remove the ith address from list

addresses.add(i, new Address(nm,st,no)); // add a new address with the input name, street and number at ith index

return i; // return the index i

}

}

// if no address match, add the business at the end of the list

addresses.add(new Address(nm,st,no));

return addresses.size()-1; // return the last index

}

}

//end of AddressBook.java

5 0
3 years ago
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