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lesantik [10]
2 years ago
5

A sample of 4 different calculators is randomly selected from a group containing 12 that are defective and 33 that have no defec

ts. What is the probability that at least one of the calculators is defective?
Mathematics
1 answer:
Aleks04 [339]2 years ago
7 0

The probability that at least one of the calculators is defective is : 0.725

<h3>What is probability?</h3>

Probability is the likelihood of an event happening or not.

if there is certainty that the event would happen probability is 1.

Analysis:

probability = required outcome/possible outcome

for 33 good calculators and 12 defective calculators, total calculators = 45

4 calculators were chosen, possible outcome = 45C4 = 148995

Required outcome = 33C3 . 12C1 + 33C2 . 12C2 + 33C1 . 12C3 + 33C0 . 12C4

= 65472 + 34848 + 7260 + 495 = 108075

Probability = 108075/148995 = 0.725

Learn more about Probability: brainly.com/question/25870256

#SPJ1

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The probability density of a random variable X is given in the figure below.
Fiesta28 [93]

Answer:

0.47

Step-by-step explanation:

First, find P(X > 1.18).

(2 − 0) / 1 = (2 − 1.18) / x

2x = 0.82

x = 0.41

Next, find P(X < 0.12).

(2 − 0) / 1 = (0.12 − 0) / x

2x = 0.12

x = 0.06

So the total probability is 0.41 + 0.06 = 0.47.

6 0
3 years ago
If a tires k=0.85, what does this tell you about the tire installed on the car as opposed to the factory-installed tire?
Gala2k [10]

Answer: since I don’t understand this question I’m choosing D

Step-by-step explanation:

8 0
3 years ago
Which of the following functions represent exponential decay?
Zina [86]

Option C: $f(x)=3^{5}\left(\frac{1}{3}\right)^{x}$ is the function that represent exponential decay.

Explanation:

The exponential decay can be represented by

$f(x)=a \cdot b^{x}$ where a>0 and 0

Option A: $f(x)=3(1.7)^{x-2}$

From the function, we can see that a=3 and b=1.7

Thus, a>0 and b>1

Thus, the function $f(x)=3(1.7)^{x-2}$ does not represent exponential decay.

Hence, Option A is not the correct answer.

Option B: $f(x)=3(1.7)^{-2 x}$

From the function, we can see that a=3 and b=1.7

Thus, a>0 and b>1

Thus, the function $f(x)=3(1.7)^{-2 x}$ does not represent exponential decay.

Hence, Option B is not the correct answer.

Option C: $f(x)=3^{5}\left(\frac{1}{3}\right)^{x}$

From the function, we can see that a=3^5=243 and b=\frac{1}{3} =0.3333

Thus, a>0 and 0

Thus, the function $f(x)=3^{5}\left(\frac{1}{3}\right)^{x}$ represent exponential decay.

Hence, Option C is the correct answer.

Option D: $f(x)=3^{5}(2)^{-x}$

From the function, we can see that a=3^5=243 and b=2

Thus, a>0 and b>1

Thus, the function $f(x)=3^{5}(2)^{-x}$ does not represent exponential decay.

Hence, Option D is not the correct answer.

8 0
4 years ago
Round 2.36 to the whole number
sukhopar [10]

I believe your answer will be 2.4 because 2 cannot be rounded up by 3 and 3 can be rounded up to 4 by 6


4 0
3 years ago
Read 2 more answers
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The first graph does. This is because of the rate of growth most likely being 5x. 
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3 years ago
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