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Oliga [24]
4 years ago
13

Which of the following functions represent exponential decay?

Mathematics
1 answer:
Zina [86]4 years ago
8 0

Option C: $f(x)=3^{5}\left(\frac{1}{3}\right)^{x}$ is the function that represent exponential decay.

Explanation:

The exponential decay can be represented by

$f(x)=a \cdot b^{x}$ where a>0 and 0

Option A: $f(x)=3(1.7)^{x-2}$

From the function, we can see that a=3 and b=1.7

Thus, a>0 and b>1

Thus, the function $f(x)=3(1.7)^{x-2}$ does not represent exponential decay.

Hence, Option A is not the correct answer.

Option B: $f(x)=3(1.7)^{-2 x}$

From the function, we can see that a=3 and b=1.7

Thus, a>0 and b>1

Thus, the function $f(x)=3(1.7)^{-2 x}$ does not represent exponential decay.

Hence, Option B is not the correct answer.

Option C: $f(x)=3^{5}\left(\frac{1}{3}\right)^{x}$

From the function, we can see that a=3^5=243 and b=\frac{1}{3} =0.3333

Thus, a>0 and 0

Thus, the function $f(x)=3^{5}\left(\frac{1}{3}\right)^{x}$ represent exponential decay.

Hence, Option C is the correct answer.

Option D: $f(x)=3^{5}(2)^{-x}$

From the function, we can see that a=3^5=243 and b=2

Thus, a>0 and b>1

Thus, the function $f(x)=3^{5}(2)^{-x}$ does not represent exponential decay.

Hence, Option D is not the correct answer.

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Answer:

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then

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Step-by-step explanation:

Equal amounts are 8549.7 from 30 mowers a+b = small and large.

If we use this as an even and take away a+b at different equations we can find the answer to be 8379.70 on the 2nd equation. First equation = 8579.70

8549.7- 249.99-249.99+329.99 to equal the given year to find c in first equation and total in year = t within the above equation.

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For what values of x is the trinomial 2x^2-x+55 equal to the square of binomial x+5
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Answer:

x = 6 , 5. For these values of x they are equal.

Step-by-step explanation:

2x²  - x + 55 =(x +5)²

2x² - x + 55 = x² + 2*x*5 + 5²

2x² - x + 55 = x² + 10x + 25

2x² - x + 55 - x²  - 10x - 25 = 0

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x² - 11x + 30 = 0

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x - 6 = 0 ;  x - 5 = 0

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d)

X    |    P(X)

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0    |    0.42

1     |    0.50

2    |    0.08

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Step-by-step explanation:

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The probability of losing the second game, given that the first game was lost is:

P(G_2=L|G_1=L)=1-P(G_2=W|G_1=L)=1-0.3=0.7

So the probability of losing both games is:

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X=2 is when both games are won. This happens with probability P=0.08.

X=1 is when one game is won and the other is lost. This happens with probability P=1-0.42-0.08=0.50.

Then the table of probabilities become:

X    |    P(X)

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0    |    0.42

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