Step-by-step explanation:
the diagonals of a parallelogram are crossing each other exactly at their midpoints. that means the lengths of both sides of a diagonal are equal.
so, we get
x = 7y - 16
and
2x + 5 = 5y
we can use the first equation as an identity directly in the second equation and get
2(7y - 16) + 5 = 5y
14y - 32 + 5 = 5y
14y - 27 = 5y
9y - 27 = 0
9y = 27
y = 3
x = 7y - 16 = 7×3 - 16 = 21 - 16 = 5
Answer: The slope is 4x.
Step-by-step explanation: First, subtract 4y from both sides to get 16x-4y=1. Next, subtract 16x from both sides to get -4y=-16x+1. Finally, divide all terms by -4 to get y=4x-0.25. The slope is represented by 4x.
11.
-1 | 4 ( 1/3 ) | 4/9
0 | 4 ( 1 ) | 4
1 | 4 ( 3 ) | 12
2 | 4 ( 9 ) | 36
The answer to the selected question is: The graph of x^2 means that it is a quadratic line
Answer:
x = 9/2
Step-by-step explanation:
The outside triangle is also a right triangle, with hypotenuse 8 and side 6.
The missing side can be calculated with pythagoras as:
![\sqrt{8^2-6^2} = \sqrt{28}](https://tex.z-dn.net/?f=%5Csqrt%7B8%5E2-6%5E2%7D%20%3D%20%5Csqrt%7B28%7D)
Now for the vertical line, lets call it y, which is a side for two "back to back" triangles, you can do pythagoras twice:
left triangle:
right triangle: ![y^2 + x^2 = 6^2](https://tex.z-dn.net/?f=y%5E2%20%2B%20x%5E2%20%3D%206%5E2)
Eliminating y², you can solve:
![28 - (8-x)^2 = 36 - x^2](https://tex.z-dn.net/?f=28%20-%20%288-x%29%5E2%20%3D%2036%20-%20x%5E2)
![28 -x^2 + 16x - 64 = 36 - x^2](https://tex.z-dn.net/?f=28%20-x%5E2%20%2B%2016x%20-%2064%20%3D%2036%20-%20x%5E2)
![16x = 36 + 64 - 28](https://tex.z-dn.net/?f=16x%20%3D%2036%20%2B%2064%20-%2028)
![x = \frac92](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac92)