Answer:
a) x=105/3 = 35 b) x=6. c) x=90
Step-by-step explanation:
A) 3x-5=100. To solve this we first add 5 to both sides and we get 3x=105. Then we divide both sides by 3 to find x. We then get x = 105/3 which simplifies to 35. To double check we can put 35 back into the equation and we get 3(35)-5=100 and we get 105-5=100. 100=100 Check
b)6 (x-4) = 12. First we need to divide both sides by 6. then after dividing both sides by 6 we are left with (x-4) = 2. Then we must add both sides by 4 to find x. We will then get x =6. To double check we can put 6 back into the equation and we get 6 (6-4) = 12 and we get 6(2) = 12. 12=12 check
c) 1/3x - 10 = 20. First we need to add 10 to both sides and we end up with 1/3x = 30. Then you can simplify this two ways. Either multiply both sides by 3 or divide both sides by 1/3, either way you will get the same answer. This will leave you with x = 90. To double check we can put 90 back into the equation and we get 1/3(90) - 10 = 20 and we get 30-10 = 20. 20=20 check
15 7/11 I think im not sure
Answer:
$16
Step-by-step explanation:
This method is probbaly working backwards. I'm not sure.
12 - 4 = 8 (How much she was left with if she didn't wash the car for 4 dollars)
8 x 2 = 16 (They mentioned she spent half of her weekly allowance)
Answer:
1110
Step-by-step explanation: If it was multiplication it would 1110 but you cat divide 185 by 6 so if it was 186, not 185 and you divided by 6 you would get 31 hope this helps
Are there choices? The answer without choices
g(x) = f(x) + 3
Find the value of a
It could be f(x) = a(x - 1)^2 so you have to check out the value of a
f(x) = y = a(x - 1)^2 Let x = 3
f(x) = y = a(3 -1)^2
4 = 2^2 * a The 4 comes from the graph. Follow 3 up until it hits f(x) then read across on the y axis.
a = 2^2 / 4
a = 1
Conclusion
f(x) = a(x - 1)^2
f(x) = (x - 1)^2
find g(x)
Just looking at the bottom point (the minimum of f(x) and g(x) ) you see that g(x) is 3 units above f(x)
So g(x) = (x - 1)^2 + 3
So g(x) = f(x) + 3 <<<<<<<< answer.
If there are choices, please list them. I am changing this at the request of a mod. Without choices, I believe either answer to be correct.
