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Illusion [34]
2 years ago
10

What is the product? Assume x≥0.

Mathematics
1 answer:
lys-0071 [83]2 years ago
4 0

The product of (√3x + √5)(√15x+2√30) assuming x ≥ 0 is 3√5x² + 6√10x + 5√3x + 10√6

<h3>What is the product of the expression?</h3>

It follows from the task content that the expression given whose product is to be evaluated is;

(√3x + √5)(√15x+2√30)

Hence, by multiplying the terms with each other accordingly; we have;

= (√45x² + 2√90x + √75x + 2√150)

= 3√5x² + 2√90x + √75x + 2√150

= 3√5x² + 2×3√10x + √75x + 2√150

= 3√5x² + 2×3√10x + 5√3x + 2√150

= 3√5x² + 2×3√10x + 5√3x + 10√6

= 3√5x² + 6√10x + 5√3x + 10√6

Ultimately, the product of the expression is; 3√5x² + 6√10x + 5√3x + 10√6

Learn more about product:

brainly.com/question/10090998

#SPJ1

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NemiM [27]

Step-by-step explanation:

2x-3x=5+10

-x=15

X=-15

2x+1=0.... 1

X-1=0

X=1......2

Substitute the value of x in equation 1

2*1+1=0

2=1

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3 years ago
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Emily has 140 books. If Frank were to triple the number of books that he now owns, he would still have fewer than Emily has.
aniked [119]
B * 3 < 140
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3 years ago
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A sector of a circle of radius is 15Cm, and angle 216 degrees is bent to form a cone. What is base radius of the cone and the ve
-Dominant- [34]

Answer:

Step-by-step explanation:

Radius r = 15

Circumference = 2πr = 30π cm

Circumference of cone = arc length of sector

= 30π × 216°/360°

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Radius of base of cone = 18π/(2π) = 9 cm

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3 0
3 years ago
Find the radical equivalent of 27^2/3 and compute it.<br> please help i'm taking a test.
AveGali [126]
Note that (a^b)^c=a^(bc) so in this case we have:

(27^(1/3))^2  the cube root of 27=±3

(±3)^2  and ±3^2=9

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I am assuming that you meant 27^(2/3)
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Answer:

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Step-by-step explanation:

Area of the triangular prism = Base Area * Height of the pyramid

A = BH/3

Get the area of the triangle

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Base of the triangle = 5

height = √5²-2.5²

h = √25-6.25

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Area of the triangular pyramid = 10.82*7.2/3

Area of the triangular pyramid = 25.98units³

Hence the area triangular pyramid is 25.98units³

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