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WARRIOR [948]
3 years ago
11

2x + y = 1 in slope-intercept form. :) also how is your day going so far?

Mathematics
2 answers:
Svetllana [295]3 years ago
4 0

Answer:

y=-2x+1

Step-by-step explanation:

2x+y=1

y=-2x+1

nnd my day has been pr good :)

kiruha [24]3 years ago
3 0

Answer:

y=-2x+1

Step-by-step explanation:

I hope this helps. I'm doing great.

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Please help me! WILL MARK BRAINLIEST
AURORKA [14]

Answer:

r=45,041

Step-by-step explanation:

455=(94)(22)^2/r

455=(94)(484)/r

455=45,496/r

455r=45,496

r=45,041

7 0
3 years ago
Read 2 more answers
Which unit of measure is the most reasonable to measure the length from your house to the grocery store?
Anit [1.1K]
B. miles because its a longer distance with leads to a smaller number
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3 years ago
How do i find the roots of this equation: f(x) = 2x5 - 9x4 + 12x3 - 12x2 + 10x - 3 = 0
Fantom [35]
The equation is <span>f(x) = 2x5 - 9x4 + 12x3 - 12x2 + 10x - 3 = 0
remark:
the sum of coefficients is = 2-9+12-12+10-3=-7+7=0, so a=1 is a zero of f
f can be written as </span>f(x) = (x-1)Q(x), and f(x) / (x-1)= Q(x)
after euclid's division
Q(x) = 2x4 - 7x3 + 5x2 - 7x +3
so for finding the other roots, making Q(x) for product of factors is a must
4 0
3 years ago
Simplify the next two expressions
prisoha [69]
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4 0
4 years ago
Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

Subtracting both distances we get

8\sqrt{2}-6\sqrt{2}  =2\sqrt{2}

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0
3 years ago
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