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lutik1710 [3]
2 years ago
6

Simplify square root one minus cos squared theta, need explanation please​

Mathematics
1 answer:
Maurinko [17]2 years ago
8 0
When you square root something’s it’s times by the same number
-1 squared =-1•-1
1•1=1
-•-=+
-1•-1=+1
=1
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Suppose a club publishes a newsletter. Expenses are$.50 for printing and mailing each copy, plus$300 total for research and writ
luda_lava [24]

200 copies must be  sold

n= number od newsletters

0,50*n+300=2,00*n

300=1,5*n

Divide both sides by 1,5

200=n

0,50*200+300=2*200

100+300=400

400=400



5 0
3 years ago
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Figure ABCD is a rhombus where the m∠ABC = 84 and m∠ABE = 3x − 6. Solve for x. Rhombus ABCD with diagonals AC and BD and point E
bazaltina [42]

Answer:

<u> x = 16</u>

Step-by-step explanation:

See the attched figure

We should know that, one of the properties of the rhombus is the diagonals bisect the angles of the rhombus.

Given:

m∠ABC = 84  and m∠ABE = 3x − 6

So, m∠ABE = 0.5 * m∠ABC = 0.5 * 84 = 42

∴ 3x - 6 = 42

Solve for x

3x = 42 + 6 = 48

x = 48/3 = 16

<u>∴ x = 16</u>

4 0
3 years ago
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The density of a fish tank is 0.3 fish over feet cubed. There are 15 fish in the tank. What is the volume of the tank?
ale4655 [162]
Since Density = mass/ volume (d = m / v), and assuming the 15 fish weigh 1 gram each - if weight of each fish isn't given -  (making that a total of 15 grams), 

D = m / v
0.3 = 15 / v 
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Hope this answers your question correctly :) 

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5 0
3 years ago
NO LINKS!!!! Find the equation of the circle below​
inysia [295]

Answer:

(x+3)^2+(y-2)^2=9

Step-by-step explanation:

<u>Equation of a circle</u>

(x-a)^2+(y-b)^2=r^2

where:

  • (a, b) is the center
  • r is the radius

From inspection of the diagram, the center of the circle <em>appears</em> to be at point (-3, 2), although this is not very clear.  Therefore, a = -3  and  b = 2.

Substitute these values into the general form of the equation of a circle:

\implies (x-(-3))^2+(y-2)^2=r^2

\implies (x+3)^2+(y-2)^2=r^2

Again, from inspection of the diagram, the <u>maximum vertical point</u> of the circle appears to be at y = 5.  Therefore, to calculate the radius, subtract the y-value of the center point from the y-value of the maximum vertical point:

⇒ radius (r) = 5 - 2 = 3

Substitute the found value of r into the equation:

\implies (x+3)^2+(y-2)^2=3^2

Therefore, the final equation of the given circle is:

\implies (x+3)^2+(y-2)^2=9

7 0
2 years ago
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Lapatulllka [165]

All triangles in this shape have same area as they have same base length and height length.

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Here the base is 4.2 cm and height is 2.5 cm for all the given triangles.

As a result, we can say that the area of \triangle A,  \triangle B,  \triangle C are equal.

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3 years ago
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