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3 years ago

If EG=50,and point F is 2/5 of the way between E and G

Mathematics

1 answer:

TEA [102]3 years ago

7 0

2/5 of 50 is 20. 50-20=30. Making FG=30

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A helicopter is flying from Hong Kong to Jakarta. The latitude of Jakarta is -6.20°, and its longitude is 106.80°. The latitude

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This is simply a piece-wise addition. You are going from 22.27 to -6.20 in latitude, and from 114.15 to 106.80 in longitude. Do the mathematics, and you get -28.47 degrees of latitude, and -7.35 degrees of longitude.

-28.47 degrees of latitude, and -7.35 degrees of longitude

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Step-by-step explanation:

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Find the derivative of the function y=x^3-8x^2+21x+1

aleksandrvk [35]

$y=x^3-8x^2+21x+1 \\
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3 years ago

What is the difference x + 5/ x + 2 - x + 1 /x^2 + 2x

xxTIMURxx [149]

2x^3 + 2x^2 + 5x + 1/ x^2

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The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9

mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

The height $h(t)$ of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation $h(t) = 3 +90\cdot t -16\cdot t^{2}$ , where $t$ is time in seconds. After how many seconds will the ball be 84 feet above the ground.

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

$3+90\cdot t -16\cdot t^{2} = 84$

$16\cdot t^{2}-90\cdot t +81 = 0$ (1)

By Quadratic Formula:

$t_{1,2} = \frac{90\pm \sqrt{(-90)^{2}-4\cdot (16)\cdot (81)}}{2\cdot (16)}$

$t_{1} = 4.5\,s$ , $t_{2} = 1.125\,s$

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

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3 years ago