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Yuki888 [10]
2 years ago
15

Identify the correctly constructed ALTER TABLE statement to add a UNIQUE constraint to the column customer_number with the const

raint name customer_number_unique on the table called 'customer'.
Computers and Technology
1 answer:
SVEN [57.7K]2 years ago
5 0

ALTER TABLE customer ADD CONSTRAINT customer_number_unique UNIQUE (customer_number);

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Answer:

Explanat500,000ion:

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3 years ago
What are some methods the researcher can use to avoid the impact of their recency bias?
dusya [7]

The methods that researcher do use to avoid the impact of their recency bias is that:

  • Option C. Record each interview that they conduct.
  • Option D. Take detailed notes during interviews.

<h3>What are some ways to lower the influence of bias when conducting user research?</h3>

The ways to lower the influence of bias when conducting user research include:

  • A person need to ask  open-ended questions. So not push people towards a given outcome.
  • Ask users to tell what is important to them.
  • Set your  objectively weight based on your findings.

Therefore, The methods that researcher do use to avoid the impact of their recency bias is that:

  • Option C. Record each interview that they conduct.
  • Option D. Take detailed notes during interviews.

Learn more about recency bias from

brainly.com/question/24491228

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See full question below

Consider the following scenario:

Imagine that a UX designer creates an app for saving, organizing, and streaming podcasts. To learn about user experiences with their product, the designer conducts interviews with a select group of target users: podcast enthusiasts. The researcher interviews 10 respondents and remembers the end of the last interview most clearly. The researcher uses this final interview to guide their thinking.

What are some methods the researcher can use to avoid the impact of their recency bias? Select all that apply.

A. Hire an outside research team to conduct the interviews

B. Survey large groups of people to supplement the interviews

C. Record each interview that they conduct

D. Take detailed notes during interviews

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1 year ago
Stream control transmission protocol (sctp) is a new _________ protocol.
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Stream control transmission protocol (sctp) is a new IP transport protocol.
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4 years ago
A certain string-processing language offers a primitive operation which splits a string into two pieces. Since this operation in
Nostrana [21]

Answer:

Explanation:

First we define define cost(i,j) to be the cost of cutting the string from index i to j. Then,

cost(i,j) = min {length of substring + cost(i,k) + cost(k,j) where i < k < j}

void  s_cut()    

 {

   int l,p;

   int temp=0;

   //ArrayList<Integer> al = new ArrayList<Integer>();

   int al[];

   Scanner s=new Scanner(System.in);

   int table[][];

   ArrayList<Integer> values[][];

   int low=0,high=0;

   int min=0;

   l=s.nextInt();

   p=s.nextInt();

   System.out.println("The values are "+l+"  "+p);

   table= new int[l+1][l+1];

   values= new ArrayList[l+1][l+1];

   al= new int[p];

   for(int i=0;i<p;i++)

   {

       al[i]=s.nextInt();

   }

   for(int i=0;i<=l;i++)

   for(int j=0;j<=l;j++)

       values[i][j]=new ArrayList<Integer>();

   System.out.println();

   for(int i=1;i<=l;i++)

       table[i][i]=0;

   //Arrays.s

   Arrays.sort(al);

   for(int i=0;i<p;i++)

   {

       System.out.print(al[i]+ "  ");

   }

   for(int len=2;len<=l;len++)

   {

       //System.out.println("The length is  "+len);

       for(int i=1,j=i+len-1;j<=l;i++,j++)

       {

           high= min_index(al,j-1);

           low= max_index(al,i);

           System.out.println("Indices are "+low+"  "+high);

           if(low<=high && low!=-1 && high!=-1)

           {

           int cost=Integer.MAX_VALUE;;

           for(int k=low;k<=high;k++)

           {

               //if(al[k]!=j)

               temp=cost;

               cost=Math.min(cost, table[i][al[k]]+table[al[k]+1][j]);

               if(temp!=cost)

               {

                   min=k;  

                   //values[i][j].add(al[k]);

                   //values[i][j].addAll(values[i][al[k]]);

                   //values[i][j].addAll(values[al[k]+1][j]);

                   //values[i][j].addAll(values[i][al[k]]);

               }

               //else

               //cost=0;

           }

           table[i][j]= len+cost;

           values[i][j].add(al[min]);

           //values[i][j].addAll(values[i][al[min]]);

           values[i][j].addAll(values[al[min]+1][j]);

           values[i][j].addAll(values[i][al[min]]);

           }

           else

               table[i][j]=0;

           System.out.println(" values are "+i+"  "+j+"  "+table[i][j]);

       }

   }

   System.out.println(" The minimum cost is "+table[1][l]);

   //temp=values[1][l];

   for(int e: values[1][l])

   {

       System.out.print(e+"-->");

   }

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