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2 years ago

Translate this sentence into an equation. the product of jenny's height and 4 is 52.

Mathematics

1 answer:

Zanzabum2 years ago

4 0

Answer:

4J = 52

Step-by-step explanation:

If Jenny's height is J:

4J = 52

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Find the area of the regular trapezoid. The figure is not drawn to scale. The top side is 4, the bottom side is 7, and both side

svp [43]

A regular trapezoid is shown in the picture attached.

We know that:
DC = minor base = 4
AB = major base = 7
AD = BC = lateral sides or legs = 5

Since the two legs have the same length, the trapezoid is isosceles and we can calculate AH by the formula:

AH = (AB - DC) ÷ 2
= (7 - 5) ÷ 2
= 2 ÷ 2
= 1

Now, we can apply the Pythagorean theorem in order to calculate DH:
DH = √(AD² - AH²)
= √(5² - 1²)
= √(25 - 1)
= √24
= 2√6

Last, we have all the information needed in order to calculate the area by the formula:

$A = \frac{(AB + CD)DH}{2}$

A = (7 + 5) × 2√6 ÷ 2
= 12√6

The area of the regular trapezoid is 12√6 square units.

7 0

3 years ago

Dana is purchasing a new car that costs $24,650. The bank is charging 4% simple interest for 6 years to finance the car. Using I

tia_tia [17]

Answer:

5,916

$24650 \times 0.04 \times 6 = 5916$

4 0

3 years ago

On a 4 1/2 hour trip Leslie drove 2/3 of the time for how many hours did Leslie drive

Greeley [361]

Answer:

3 hours

Step-by-step explanation:

4.5*(2/3)

= 3 hours

8 0

3 years ago

Read 2 more answers

If the theoretical probability of a event occurring is 5/7 what is the theoretical probability of the event not occurring

IgorC [24]

2/7 of a chance of it not occurring

3 0

2 years ago

Read 2 more answers

What is the horizontal asymptote for y(t) for the differential equation dy dt equals the product of 2 times y and the quantity 1

marta [7]

First, we need to solve the differential equation.
$\frac{d}{dt}\left(y\right)=2y\left(1-\frac{y}{8}\right)$
This a separable ODE. We can rewrite it like this:
$-\frac{4}{y^2-8y}{dy}=dt$
Now we integrate both sides.
$\int \:-\frac{4}{y^2-8y}dy=\int \:dt$
We get:
$\frac{1}{2}\ln \left|\frac{y-4}{4}+1\right|-\frac{1}{2}\ln \left|\frac{y-4}{4}-1\right|=t+c_1$
When we solve for y we get our solution:
$y=\frac{8e^{c_1+2t}}{e^{c_1+2t}-1}$
To find out if we have any horizontal asymptotes we must find the limits as x goes to infinity and minus infinity.
It is easy to see that when x goes to minus infinity our function goes to zero.
When x goes to plus infinity we have the following:
$$$\lim_{x\to\infty} f(x)$$=y=\frac{8e^{c_1+\infty}}{e^{c_1+\infty}-1} = 8$
When you are calculating limits like this you always look at the fastest growing function in denominator and numerator and then act like they are constants.
So our asymptote is at y=8.

3 0

3 years ago