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mihalych1998 [28]
3 years ago
10

Find the error & explain why it is wrong:

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
8 0

( { \frac{4 {x}^{3} }{ {y}^{4} }) }^{ - 2}  =  \frac{16x {}^{6} }{ {y}^{8} }

\frac{(4 {x}^{3})^{ - 2}  }{ { {(y}^{4} )}^{ - 2} }  =  \frac{16 {x}^{6} }{ {y}^{8} }

\frac{ {16x}^{ - 6} }{ {y }^{ - 8} }  = \frac{ {16x}^{6} }{ {y}^{8} }

The power of -2 was mistook as 2.

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