All categories

2 years ago

What are the characteristics of most unsaturated fatty acids found within a human cell?.

1 answer:

4 0

The characteristics of most unsaturated fatty acids found within a human cell are deprotonated carboxylic acid and cis double bonds.

With the exception of steroids, fatty acids are carboxylic acids that provide the structural foundation of fats, oils, and all other types of lipids. More than 70 have been found in the natural world.
They are typically unbranched, contain an even number of carbon atoms (often 12–20), and can be divided into groups based on the existence and quantity of carbon–carbon double bonds.
As a result, saturated fatty acids don't have any carbon-to-carbon double bonds, while monounsaturated fatty acids have one, and polyunsaturated fatty acids have two or more.

learn more about unsaturated fatty acids here: brainly.com/question/3007736

#SPJ4

You might be interested in

Science help pls,, thank

Schach [20]

<h2>HEYA DEAR! HERE'S YOUR ANSWER.</h2>

THE ANSWER TO YOUR QUESTION US CONVERGENT .

6 0

3 years ago

One way that mining for mineral resources damages land is by?

ValentinkaMS [17]

Well it does increase soil erosion.

6 0

3 years ago

Read 2 more answers

Which of the following cases represents the phenomenon of contact inhibition? a. Healing of an injury b. Growth of a tumor c. Tu

raketka [301]

<span>b. Growth of a tumor

</span><span>The phenomenon of contact inhibition occurs when normal cells doesn's stop dividing when in collision with another cell which triggers cancerous cells.</span>

8 0

3 years ago

Need help with these asap

emmainna [20.7K]

I believe it goes in the following order top down

1 5 3 4 2.

5 0

3 years ago

In a population of plants, the allele for long stems (S) is completely dominant over the allele for short stems (s). If 35% of t

Sergio [31]

Answer:

The correct answer would be 48 percent.

It can be solved by using the Hardy-Weinberg equation.

p² + 2pq+ q² = 1

p + q = 1

where, p² represents homozygous dominant's frequency that is, SS in this case,

q² represents homozygous recessive's frequency that is, ss in this case,

2pq represents heterozygous dominant's frequency that is, Ss in this case.

p represents dominant allele's frequency and q represents the recessive allele's frequency.

Now, the percentage of homozygous recessive or short stems is 35%. Therefore, the frequency of homozygous recessive would be 0.35.

Thus, the value of q² = 0.35

So, q = $\sqrt{0.35}$ = 0.59 which is approximately equals to 0.6.

As p + q = 1 so, q = 1 - 0.6 = 0.4

The frequency of heterozygous (Ss) = 2pq = 2(0.6)(0.4) = 0.48

Hence, the frequency of heterozygous would be 48 percent.

8 0

3 years ago