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Harlamova29_29 [7]
2 years ago
9

Find the value of 7 + 15 + 23 +...+ 767 + 775 + 783

Mathematics
1 answer:
Serggg [28]2 years ago
7 0

Answer:

38,710.

Step-by-step explanation:

This is an arithmetic series  with common difference  8 , first term a = 7 and last term L = 783.

The number of terms n = (783 - 7) / 8 + 1 = 98

Sum of 98 terms = (n/2)[a + L)

= (98/2)(7 + 783)

= 49 * 790

= 38,710.

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Find three consecutive positive integers such that the sum of their squares is 2354. What is the largest integer?
Ilya [14]

Answer:

The largest integer is 29.

Step-by-step explanation:

Let the consecutive positive integers are x, x+1 and x+2.

The square of sum of squares of three consecutive positive integers is 2354 such that,

x^2+(x+1)^2+(x+2)^2=2354\\\\x^2+x^2+2x+1+x^2+4+4x=2354\\\\3x^2+6x+5=2354\\\\3x^2+6x- 2349=0

It is a quadratic equation whose solution is given by :

x = 27 and x = -29

First positive integer = 27

Second positive integer = 27+1 = 28

Third positive integer = 27+2 = 29

Hence, the largest integer is 29.

4 0
3 years ago
Jim's personal fitness tracker tells him that he ran a distance of 15.2175 kilometers. Round 15.2175 to the nearest hundredth.
cluponka [151]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Find the value of x.
Helen [10]
The vertical of x is 100 degrees meaning the opposite will be 80 degrees because they always add up to 180 degrees.
7 0
3 years ago
Evaluate the double integral. . ∫∫ y sqrt(x^2-y^2) dA, R={(x,y)|0≤y≤x, 0≤x≤1}. R. . Please explain
polet [3.4K]
First we will evaluate: ( substitution: u = x² - y²,  du = - 2 y dy )
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=- \frac{1}{3} (  \sqrt{( x^{2} - x^{2}) ^{3}  }  -  \sqrt{ (x^{2} -0 ^{2} ) ^{3} } =
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1/3\int\limits^1_0 { x^{3} } \, dx = 1/3 (  x^{4}/4)}= 1/3 ( 1 ^{4}/4 - 0^{4} /4 )
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4 0
3 years ago
Does anyone know how to solve this?
Romashka [77]

Answer:

yea you have to line it up

8 0
3 years ago
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