_Does anyone wann help me wit something ill give you bloxburg (from ro _blox) money if u know how to do it!And yes it’s math _4
Answer:
![\Large \boxed{\mathrm{Option \ 2}}](https://tex.z-dn.net/?f=%5CLarge%20%5Cboxed%7B%5Cmathrm%7BOption%20%5C%202%7D%7D)
Step-by-step explanation:
![2x^2 =16](https://tex.z-dn.net/?f=2x%5E2%20%3D16)
The square root property requires a quantity squared by itself on one side of the equation. The only quantity squared is x, so divide both sides by 2 before applying the square root property.
The x variable should be isolated on one side of the equation. The x variable is squared so before performing the square root property where we take the square root of both sides, we divide both sides by 2, then take the square root of both sides.
Dividing both sides by 2.
![\displaystyle \frac{2x^2 }{2} =\frac{16}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B2x%5E2%20%7D%7B2%7D%20%3D%5Cfrac%7B16%7D%7B2%7D)
![x^2 =8](https://tex.z-dn.net/?f=x%5E2%20%3D8)
Taking the square root of both sides.
![\sqrt{x^2 } =\pm \sqrt{8}](https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E2%20%7D%20%3D%5Cpm%20%5Csqrt%7B8%7D)
![x=\pm 2\sqrt{2}](https://tex.z-dn.net/?f=x%3D%5Cpm%202%5Csqrt%7B2%7D)
Answer: 4 /15
Step-by-step explanation:
![0.2\overline{6}\\\\=0.2+\dfrac{1}{10} *\dfrac{6}{9} \\\\=\dfrac{1}{5} +\dfrac{1}{15} \\\\\\\boxed{0.2\overline{6}=\dfrac{4}{15} }\\](https://tex.z-dn.net/?f=0.2%5Coverline%7B6%7D%5C%5C%5C%5C%3D0.2%2B%5Cdfrac%7B1%7D%7B10%7D%20%2A%5Cdfrac%7B6%7D%7B9%7D%20%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B5%7D%20%2B%5Cdfrac%7B1%7D%7B15%7D%20%5C%5C%5C%5C%5C%5C%5Cboxed%7B0.2%5Coverline%7B6%7D%3D%5Cdfrac%7B4%7D%7B15%7D%20%7D%5C%5C)
The probability (rounded to the nearest whole percent) that a randomly selected gym member would buy passion fruit vitamin water but not tropicalgrape vitamin water is 17 percent.
Let's take a look at a perfect square trinomial.
![(x+7)^2](https://tex.z-dn.net/?f=%28x%2B7%29%5E2)
We can distribute this expression to get
![x^2+14x+49](https://tex.z-dn.net/?f=x%5E2%2B14x%2B49)
.
An important relation to recognize here is that the constant is the square of half of the x value.
Now, if we wanted to add a number to
![x^2+16x](https://tex.z-dn.net/?f=x%5E2%2B16x)
to make a perfect square trinomial, we could have the value of x and then square it.
Half of 16 is 8, and 8 squared is