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stich3 [128]
2 years ago
15

Help please and thank you

Mathematics
1 answer:
babymother [125]2 years ago
6 0
<h3>Answer: Draw a straight line through (0,-7) and (1,-5)</h3>

Explanation:

You could use any two points you want. For me, the easiest is when x = 0. Plug this into the equation to get

y = 2x-7

y = 2(0)-7

y = -7

So we have x = 0 and y = -7 pair up to get (0,-7) as our first point. This is the y intercept.

Repeat for x = 1

y = 2x-7

y = 2(1)-7

y = -5

So (1,-5) is another point on this line. You only need two points at minimum to graph a straight line.

You might be interested in
Add [1/5x-4+2y]+[2/5x+5-4y]=
alisha [4.7K]
<h3>I'll teach you how to solve (1/5x-4+2y)+(2/5x+5-4y)</h3>

-----------------------------------------------------------------

(1/5x-4+2y)+(2/5x+5-4y)

Remove parentheses:

1/5x-4+2y + 2/5x+5-4y

Group like terms:

1/5x+2/5x+2y-4y-4+5

Add similar elements:

3/5x+2y-4y-4+5

Add similar elements:

3/5x-2y-4+5

Multiply:

3x/5-2y-4+5

Add subtract the numbers:

3x/5+1-2y

Your Answer Is 3x/5+1-2y

plz mark me as brainliest :)

6 0
3 years ago
Match the sequences with the type of sequence (arithmetic or geometric).
Anni [7]
9, 4, -1, -7
Arithmetic because it has a common difference of 5.

4, 10, 16, 22
Arithmetic because it has a common difference of 6.

2, -6, 18, -54
Geometric because it has a common ratio of -3.

4, 4, 4, 4
Both because it has a common difference of 0 and a common ratio of 1.

Hope this helps :)
3 0
3 years ago
Can someone help me
MArishka [77]

Answer:

ok

Step-by-step explanation:

9+10=21

5 0
3 years ago
Through: (6, 2), perpendicular to<br> y = -x-5 <br> in slope intercept form
True [87]

Answer:

y = x-4

Step-by-step explanation:

y = -x-5

Slope of line is -1.

Slope of perpendicular to line is 1.

Point-slope equation for line of slope 1 that passes through (6,2):

y-2 = 1(x-6)

Rearrange equation to slope-intercept form:

y = 1(x-6) + 2

y = x-4

6 0
2 years ago
Need help pls thxs. you​
ale4655 [162]

Answer:

The second expression is the product of the above expressions.....

8 0
3 years ago
Read 2 more answers
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