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2 years ago

When f(a) = 227 + 32 - 3, evaluate f( - 1) helpp

Mathematics

1 answer:

Hoochie [10]2 years ago

7 0

Step-by-step explanation:

$f(x) = 2 {x}^{2} + 3x - 3$

$f( - 1) = 2. {( - 1)}^{2} + 3.( - 1) - 3$

$f( - 1) = 2 - 3 - 3$

$f( - 1) = - 4$

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Hello!

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3 years ago

Read 2 more answers

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Answer: 1. A) 2/5 B) X= -5 Y= 2

2. A) -3/2 B) X= 2 Y= 3

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Step-by-step explanation: A) Look where the line intersects perfectly through a corner of one of the boxes, find the next one closes to that count how many it goes up and how many across. Rise/Run so the amount it goes up goes on the top of the fraction and the amount across on the bottom of the fraction.

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3 years ago

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The length and width of the rectangle would be 20*4 or 10*8. hope that helped

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4 years ago

Rachel has a collection of 40 stuffed animals. 3/8 of the animals are bears and are dogs. How many bears and dogs does she have?

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4 years ago

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The two events out of the listed events which are independent events are given by: Option A: A and C

<h3>What is chain rule in probability?</h3>

For two events A and B, by chain rule, we have:

$P(A \cap B) = P(B)P(A|B) = P(A)P(A|B)$

<h3>What is law of total probability?</h3>

Suppose that the sample space is divided in n mutual exclusive and exhaustive events tagged as

$B_i \: ; i \in \{1,2,3.., n\}$

Then, suppose there is event A in sample space.

Then probability of A's occurrence can be given as

$P(A) = \sum_{i=1}^n P(A \cap B_i)$

Using the chain rule, we get

$P(A) = \sum_{i=1}^n P(A \cap B_i) = \sum_{i=1}^n P(A)P(B_i|A) = \sum_{i=1}^nP(B_i)P(A|B_i)$

<h3>How to form two-way table?</h3>

Suppose two dimensions are there, viz X and Y. Some values of X are there as $X_1, X_2, ... , X_n$ values of Y are there as $Y_1, Y_2, ..., Y_k$ rows and left to the columns. There will be $n \times k$ values will be formed(excluding titles and totals), such that:

Value( $i^{th}$ row, $j^{th}$ column) = Frequency for intersection of $X_i$ and $Y_j$ values are going in rows, and Y values are listed in columns).

Then totals for rows, columns, and whole table are written on bottom and right margin of the final table.

For n = 2, and k = 2, the table would look like:

$\begin{array}{cccc}&Y_1&Y_2&\rm Total\\X_1&n(X_1 \cap Y_1)&n(X_1\cap Y_2)&n(X_1)\\X_2&n(X_2 \cap Y_1)&n(X_2 \cap Y_2)&n(X_2)\\\rm Total & n(Y_1) & n(Y_2) & S \end{array}$

where S denotes total of totals, also called total frequency.

n is showing the frequency of the bracketed quantity, and intersection sign in between is showing occurrence of both the categories together.

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Suppose that there are finite elementary events in the sample space of the considered experiment, and all are equally likely.

Then, suppose we want to find the probability of an event E.

Then, its probability is given as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text{Number of total cases}} = \dfrac{n(E)}{n(S)}$

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<h3>How to find if two events are independent?</h3>

Suppose that two events are denoted by A and B.

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$\begin{array}{ccccc} &\text{Public}&\text{Own}&\text{Others}&\text{Total}\\\text{Male}&12/60&20/60&4/60&36/60\\\text{Female}&8/60&10/60&6/60&24/60\\\text{Total}&20/60&30/60&10/60&1\end{array}$