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valina [46]
2 years ago
12

HELP HELP HELP HELP HELP HELP HELP

Mathematics
1 answer:
postnew [5]2 years ago
4 0

Answer:

\sqrt{16} = 4\\

Step-by-step explanation:

the distance formula for graph = \sqrt{x^{2}  + y^{2} }

<em>(simplified version)</em>

\sqrt{0^{2} + (-4)^{2} }  \\\\\\\sqrt{0 + 16} \\\\\\\sqrt{16}\\\\= 4

I hope its right TT I just looked it up here:

https://byjus.com/maths/distance-between-two-points-formula/

you should double check here as well

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A paper published in a medical journal reported that about 11/25 of girls ages 16 to 17 do not excersise at all the entire study
Wittaler [7]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Please help me solve this problem I’m really stuck on!!! Please help right now!!!
valentinak56 [21]

\frac{ ({x}^{1}  {y}^{ \frac{1}{4} })^{2}  }{ {x}^{ \frac{5}{4} }  {y}^{ \frac{5}{8} } } \\   \frac{ {x}^{2} {y}^{ \frac{2}{4} }  }{ {x}^{ \frac{5}{4} } {y}^{ \frac{5}{8} }  }  \\   \frac{ {x}^{2}  {y}^{ \frac{1}{2} } }{ {x}^{ \frac{5}{4} }  {y}^{ \frac{5}{8} } }  \\

You can distribute the exponent outside of the parentheses by multiplying it to the exponent in each term in the numerator

When dividing, subtract the exponent of the numerator by the exponent of the denominator for each variable

For x:

{x}^{2}  -  {x}^{ \frac{5}{4} }  \\  {x}^{ \frac{3}{4} }

For y:

{y}^{ \frac{1}{2} }  -  {y}^{ \frac{5}{8} }  \\  {y}^{ \frac{ - 1}{8} }  \\  \sqrt[8]{y}

EDIT: y^(-1/8) is equal to 1 / (8 radical y)

Final answer:

\frac{ {x}^{ \frac{3}{4} } }{ \sqrt[8]{y} }

5 0
3 years ago
After a company celebrated its ten year anniversary, the president of the company wanted to know how long employees have been wi
finlep [7]

Step-by-step explanation:

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Please send the box plot, I can solve it then but there is not enough info right here. Sorry!

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The following portion of a flow diagram shows that the expression (z + x)+ y is equivalent to the expression (z + y)+ x.
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The answer is:

Answer:

<u>C. 1.05</u>

if u mark as brainly thatll be cool

8 0
3 years ago
Read 2 more answers
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