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borishaifa [10]
2 years ago
5

Solve the system of equations: 8x + 3y = 13 3x + 2y = 11

Mathematics
1 answer:
Sonbull [250]2 years ago
8 0

Answer:

1.x=13/8-3y/8

2.x=11/3-2y/3

Step-by-step explanation:

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Keith bought a tree for his backyard. The graph shows the height of the tree after a certain number of years.
Vikentia [17]

Answer:18

Step-by-step explanation:

Its is 18 caycausecause the arrow is pointing next to it

1

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this is the question your grandma is in the hospital and is put on a liquid diet after examining her chart a mistake is found st
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Well the math comes out to 1102.31 pounds thats a bit unrealistic but i'm fairly sure i converted correctly.
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Which of the following representations are functions?
Hitman42 [59]
The answer to this question is a and c only
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3 years ago
Riding a proportion of 15 is 1 and a half percent of what number​
skad [1K]

Answer:

1000

Explanation:

15=1.5%

1000=100%

10=1%

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7 0
3 years ago
A 5-card hand is dealt from a perfectly shuffled deck. Define the events: A: the hand is a four of a kind (all four cards of one
TiliK225 [7]

In a hand of 5 cards, you want 4 of them to be of the same rank, and the fifth can be any of the remaining 48 cards. So if the rank of the 4-of-a-kind is fixed, there are \binom44\binom{48}1=48 possible hands. To account for any choice of rank, we choose 1 of the 13 possible ranks and multiply this count by \binom{13}1=13. So there are 624 possible hands containing a 4-of-a-kind. Hence A occurs with probability

\dfrac{\binom{13}1\binom44\binom{48}1}{\binom{52}5}=\dfrac{624}{2,598,960}\approx0.00024

There are 4 aces in the deck. If exactly 1 occurs in the hand, the remaining 4 cards can be any of the remaining 48 non-ace cards, contributing \binom41\binom{48}4=778,320 possible hands. Exactly 2 aces are drawn in \binom42\binom{48}3=103,776 hands. And so on. This gives a total of

\displaystyle\sum_{a=1}^4\binom4a\binom{48}{5-a}=886,656

possible hands containing at least 1 ace, and hence B occurs with probability

\dfrac{\sum\limits_{a=1}^4\binom4a\binom{48}{5-a}}{\binom{52}5}=\dfrac{18,472}{54,145}\approx0.3412

The product of these probability is approximately 0.000082.

A and B are independent if the probability of both events occurring simultaneously is the same as the above probability, i.e. P(A\cap B)=P(A)P(B). This happens if

  • the hand has 4 aces and 1 non-ace, or
  • the hand has a non-ace 4-of-a-kind and 1 ace

The above "sub-events" are mutually exclusive and share no overlap. There are 48 possible non-aces to choose from, so the first sub-event consists of 48 possible hands. There are 12 non-ace 4-of-a-kinds and 4 choices of ace for the fifth card, so the second sub-event has a total of 12*4 = 48 possible hands. So A\cap B consists of 96 possible hands, which occurs with probability

\dfrac{96}{\binom{52}5}\approx0.0000369

and so the events A and B are NOT independent.

4 0
3 years ago
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