3 years ago

Help please, i need this answer asap!!!

Mathematics

1 answer:

xeze [42]3 years ago

6 0

Fill in the spaces in this order and it should be right
1. 15
2. 9
3. 3
4. -3

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What is the right choice

never [62]

I think its C but not sure

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3 years ago

Mark went to costco and bought 12 cans of albacore for $15.96. what is the cost per can?

Law Incorporation [45]

Answer:

$1.33

Step-by-step explanation:

15.96 divided by 12 = $1.33

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3 years ago

Factor: d2 + 16dm + 64m2

lutik1710 [3]

Answer:

$(d + 8m)^2$

Step-by-step explanation:

$d^2 + 16dm + 64 m^2 = (d + 8m)^2$

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3 years ago

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a car traveling at 30 m/s starts to decelerate steadily. it comes to a complete stop in 12 seconds. what is its acceleration?

creativ13 [48]

Just divide -30 m/s (the change in velocity) by 12 seconds (the time required for the car to come to a stop):

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3 years ago

Find the area under the curve y = 27/x3 from x = 1 to x = t. Evaluate the area under this curve for t = 10, t = 100, and t = 100

Darina [25.2K]

Answer:

Step-by-step explanation:

given is a function as

$y=\frac{27}{x^3}$

We are to find the area form x=1 to x=t

The curve from x=1 lies in the I quadratnt.

So area above x axis is to be calculated

Area = $\int\limits^t_1 {\frac{27}{x^3} } \, dx \\=\frac{-27}{2x^2} \\= \frac{-27}{2t^2}-\frac{-27}{2}\\=\frac{27}{2}(1-\frac{1}{t^2} )$

a) When t =10,

area = $\frac{27}{2} (1-\frac{1}{10^2} )\\= 13.365$

b) t=100

area = $\frac{27}{2} (1-\frac{1}{100^2} )\\= 13.49865$

c) t=10000

area = $\frac{27}{2} (1-\frac{1}{10000^2} )\\= 13.5$

6 0

3 years ago