Answer:
Option a) 50% of output expected to be less than or equal to the mean.
Step-by-step explanation:
We are given the following in the question:
The output of a process is stable and normally distributed.
Mean = 23.5
We have to find the percentage of output expected to be less than or equal to the mean.
Mean of a normal distribution.
- The mean of normal distribution divides the data into exactly two equal parts.
- 50% of data lies to the right of the mean.
- 50% of data lies to the right of the mean
Thus, by property of normal distribution 50% of output expected to be less than or equal to the mean.
Answer:
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Step-by-step explanation:
Answer: a) 0.7
b) 70%
Step-by-step explanation:
a) There are 10 marbles.The red marbles are 7
so that 7/10
then change to decimal 7/10=0.7
b) if we get percentage *100
so, 7÷10*100%
70%
Answer:
1759.52cm^3
Step-by-step explanation:
Given data
Cylinder E
h = 30 cm and
r = 4 cm
The expression for the volume is
V= πr^2h
V= 3.142*4^2*30
V= 3.142*16*30
V=1508.16 cm^3
Cylinder F
h=5 cm
r = 4 cm
The expression for the volume is
V= πr^2h
V= 3.142*4^2*5
V= 3.142*16*5
V=251.36 cm^3
Hence the total volume is
=251.36+1508.16
= 1759.52cm^3
Answer:
The sample space would be infinite
{HH, TTTHH, TTTTHH, TTTTTTTHH.......................}
1/8
Step-by-step explanation:
The sample space would be infinite
{HH, TTTHH, TTTTHH, TTTTTTTHH.......................}.
This is because the number of times the coin would be flipped is not specified. So, you can keep flipping the coin forever.
If the coin is tossed four times then the sample space would be
{HHHH HTHH THHH HTHT
HHHT HTTH TTHH THTH
HHTT HHTH TTTH THHT
HTTT TTTT TTHT THTT}
HTHH and TTHH are the only two cases where two consecutive tosses will result in two heads
Probability that the coin will be tossed four times is 2/16 = 1/8
