A quadratic equation is usually in the form:
where a, b and c are the coefficients of the expression and a ≠ 0.
If a = 0, the equation becomes a linear expression and is no longer quadratic.
Hence, in the above options; y = 5x -2 is the only one that is not a quadratic equation.
I’m sorry I don’t get that whole situation
So consecutive intergers are 1 away from each other so
the numbers are
x,x+1,x+2
if the product (multily) of 2 smaeller is 5 less than 5 times largest so
(x times (x+1)) is 5 less than 5 times (x+2)
(x times (x+1))=-5+5(x+2)
pemdas
distribute using distributiver property
a(b+c)=ab+ac so
x times (x+1)=x^2+x
5(x+2)=5x+10
we have
x^2+x=-5+5x+10
add like terms
x^2+x=5x+5
subtract (5x+5) from both sides
x^2-4x-5=0
factor by find what 2 numbers add to -4 and multply to get -5
numbers are 1 and -5
so we do
(x+1)(x-5)=0
sete each to zero
x+1=0
x-5=0
x+1=0
sbtract 1
x=-1
we want positie so thisis wrong answer
x-5=0
add 5
x=5
subsitute
x,x+1,x+2
5,5+1,5+2
5,6,7
smalles is 5
Rsc . rrr . rrc rrs . rsr rcr crs src scr csr ccc sss
these are all the possible outcomes
12 total outcomes
