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Novosadov [1.4K]
2 years ago
12

A linear function has a slope of Negative StartFraction 7 Over 9 EndFraction and a y-intercept of 3. How does this function comp

are to the linear function that is represented by the equation y + 11 = Negative StartFraction 7 Over 9 EndFraction (x minus 18)? a It has the same slope and the same y-intercept. b It has the same slope and a different y-intercept. c It has the same y-intercept and a different slope. d It has a different slope and a different y-intercept.
Mathematics
1 answer:
dem82 [27]2 years ago
7 0

It has the same slope and the same y-intercept, that is, <u>option a</u> is the right choice.

A linear function in the slope-intercept is written as y = mx + b, where m represents the slope of the line and b represents the y-intercept.

We are given two linear functions and are asked to compare them.

<u>First </u><u>linear function:</u>

Slope (m) = -7/9.

y-intercept (b) = 3.

Therefore, the linear function is: y = (-7/9)x + 3.

<u>Second </u><u>linear function</u>:

Function given: y + 11 = (-7/9)(x - 18)

or, y + 11 = (-7/9)x + (-7/9)(-18)

or, y = (-7/9)x + 14 - 11 = (-7/9)x + 3.

Therefore, slope (m) = (-7/9)

y-intercept (b) = 3.

Therefore, we can say that it has the same slope and the same y-intercept, that is, <u>option a</u> is the right choice.

Learn more about linear functions at

brainly.com/question/15602982

#SPJ10

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Answer:

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Step-by-step explanation:

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Sub in x and y coordinates and slope then isolate for b

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b = -10/5 + 12/5

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y = (-4/5)x + 2/5

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ANSWER TO QUESTION 1


f(x)=(x-2)(x+3)(x-1)^2.



EXPLANATION


The function given to us is,


f(x)=x^4-x^3-7x^2+13x-6


According to rational roots theorem,


\pm1,\pm2,\pm3,\pm6 are possible rational zeros of  


f(x)=x^4-x^3-7x^2+13x-6.


We find out that,


f(-3)=(-3)^4-(-3)^3-7(-3)^2+13(-3)-6


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f(-3)=6-6



f(-3)=0


Also




f(2)=(2)^4-(2)^3-7(2)^2+13(2)-6



f(2)=16-8-28+26-6



f(2)=6-6



f(2)=0


This implies that  


x-2 and x+3 are factors of



f(x)=x^4-x^3-7x^2+13x-6 and hence (x-2)(x+3)=x^2+x-6 is also a factor.



We perform the long division as shown in the diagram.



Hence,


f(x)=(x-2)(x+3)(x-1)^2.


ANSWER TO QUESTION 2

Sketching the graph

We can see from the factorization that the roots  

x=2 and x=-3 have a multiplicity of 1, which is odd. This means that the graph crosses the x-axis at this intercepts.


Also the root x=1 has a multiplicity of 2, which is even. This means the graph does not cross the x-axis at this intercept.



Now we determine the position of the graph on the following intervals,


x\le -3


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f(-4)=150\:>0



-3\le x \le 1


f(0)=-6\:


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f(1.5)=-0.56\:



x \ge 2



f(3)=24\:>0



We can now use these information to sketch the function as shown in diagram



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