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igor_vitrenko [27]
2 years ago
14

Write 8n^2-13n+5 in factor form

Mathematics
1 answer:
lbvjy [14]2 years ago
8 0

Answer:

(8n - 5)(n-1)

Step-by-step explanation:

Hello!

We can factor this by grouping. We have to find two numbers that add up to -13 but multiply to 8 * 5 .

The two numbers that work are -8 and -5. Expand -13n to -8n and -5n.

<h3>Factor by Grouping</h3>
  • 8n^2 - 13n + 5
  • 8n^2 - 8n - 5n + 5
  • 8n(n -1) -5(n - 1)
  • (8n - 5)(n-1)

The factored expression is (8n - 5)(n-1).

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Answer:

Step-by-step explanation: Answer

5.0/5

1

author link

tereso536

Ambitious

17 answers

723 people helped

Answer:

The Product Sum method of factoring we use on trinomials (ax2+bx+c) with the value of a=1. This is the method that is probably used the most.

example: x2+7x+12 The product is the a value times the c value. In this case 12.

The sum is the b value. In this case 7.

Find the two numbers that multiply to 12 (the product) andadd to 7 (the sum). +4 and +3

These are your two factors. In your two binomials put the x in front and the factors in the back. (x+4)(x+3)

This is your factored expression. To check FOIL back out.

Why does this work???

example:

x2-4x-12

p= -12

s= -4 factors are -6 and +2

so factored answer is (x-6)(x+2)

example:

I'm thinking of a number that could be solved by x2+10x+16=0. What could the number be?

p=16

s=10 factors are +8 and +2

(x+8)(x+2)=0

so either x+8=0 or x+2=0 so either x= -8 or -2 is the

number.

3 0
2 years ago
Read 2 more answers
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