Answer:
Hope the picture will help you....
Note: I am not sure about my answer....
Using quadratic formula you can have a maximum of two solutions. When you set this problem equal to zero, your a=-1, b=-10, c=2
Answer:
10 Numbers
Step-by-step explanation:
Answer: 10, 11, & 12
<u>Step-by-step explanation:</u>
Let x represent the age of the youngest child.
Their ages are consecutive so,
Youngest: x
Middle: x + 1
Oldest: x + 2
The age of the Youngest squared (x²) equals 8 times the Oldest [8(x + 2)] plus 4.
x² = 8(x + 2) + 4
x² = 8x + 16 + 4
x² = 8x + 20
x² - 8x - 20 = 0
(x - 10)(x + 2) = 0
x - 10 = 0 or x + 2 = 0
x = 10 or x = -2
Since age cannot be negative, x = -2 is not valid
So, the Youngest (x) is 10
the Middle (x + 1) is 11
and the Oldest (x + 2) is 12
A: 2,5
B: 3,1
C: -2,4
Explanation:
When you’re moving right and up you would add however many numbers you moved up to the original points because going right on a graph makes the X a larger number, and going up makes it larger.
