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gizmo_the_mogwai [7]
1 year ago
5

Sec6A - tan6A = 1+3tan2A.sec2A

Mathematics
1 answer:
larisa [96]1 year ago
6 0

sec ^6 A−tan ^6A=(1+tan ^2A−tan ^2 A)(1+tan ^4

A+2tan ^2 A+tan ^2 A+tan ^4 A+tan ^4 A)

sec ^6 A−tan ^6 A=1+3tan ^2 A+3tan ^4A

L.H.S. = R.H.S.

Hence proved

Step-by-step explanation:

♡´・ᴗ・`♡

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The Marysville Fire Department was sent to rescue a cat from a tree. The firefighters laid a 25-foot ladder against the tree at
lyudmila [28]

the diffrence would be 1 foot

8 0
3 years ago
F = uv/u + v make u the subject
never [62]

I'm assuming that you mean

\dfrac{uv}{u+v}

because if you meant

\dfrac{uv}{u}+v

then u would simplify and you couldn't make it the subject.

Under this assumption, we start with

F=\dfrac{uv}{u+v}

We multiply both sides by u+v

F(u+v)=uv

We expand the left hand side:

Fu+Fv=uv

We move all terms involving u to the left and all terms not involving u to the right:

Fu-uv=-Fv

We factor u on the left hand side:

u(F-v)=-Fv

We divide both sides by F-v

u=\dfrac{-Fv}{F-v}

3 0
3 years ago
Jill Hartman earns $750 per week, plus 3% of sales in excess of $6500. if Jill sells $25000 in the first week her earnings are ?
Nezavi [6.7K]
The answer is going to be: answer B.

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7 0
3 years ago
Read 2 more answers
my neighbor has two cats and both cats have yellow eyes. therefore when to cats live together, they will both have yellow eyes.
Whitepunk [10]
Inductive reasoning has to do with coming to a certain prediction or a conclusion based on multiple true premises.
Here, we know that these two cats live together and that they have yellow eyes. These two statements are true. So, naturally, we can conclude that any two cats which live together will have yellow eyes.
Now, whether or not this is correct, that is beside the point. 
3 0
3 years ago
An elephant can run of a mile in 36 seconds. At this rate, which expression can be used to determine how fast an elephant runs i
Mice21 [21]

<u>Answer:</u>

The expression that can be used to determine how fast an elephant runs in miles per hour is 100 miles per hour

<u>Solution:</u>

Given that,

Distance covered by an elephant in 36 seconds is equal to 1 mile

Therefore, <em>distance covered by the elephant in 1 second</em> is  \frac{1}{36} mile

Therefore, <em>distance covered by the elephant in 60 seconds</em> (60 seconds = 1 minute) is

\frac{1}{36} \times 60=\frac{5}{3} \text { miles }

Therefore, <em>distance covered by the elephant in 60 minute</em> (60 minute = 1 hour) is

\frac{5}{3} \times 60=100 \text { miles per hour }

Hence the expression that can be used to determine how fast an elephant runs in miles per hour is 100 miles per hour

7 0
3 years ago
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