All categories

3 years ago

What expression is equivalent to 2(x+4)

Mathematics

1 answer:

Arte-miy333 [17]3 years ago

5 0

Answer:

2x + 8

Step-by-step explanation:

solve by using the distributive property

2(x + 4) = (2)(x) + (2)(4)

2x + 8

You might be interested in

L :V --> W is a linear transformation. Prove each of the following (a) ker L is a subspace of V. (b) range L is a subspace of

iragen [17]

Answer:

a) Assume that $x,y\in\ker L$ , and $\alpha$ is a scalar (a real or complex number).

First. Let us prove that $\ker L$ is not empty. This is easy because $L(0_V)=0_W$ , by linearity. Here, $0_V$ stands for the zero vector of V, and $0_W$ stands for the zero vector of W.

Second. Let us prove that $\alpha x\in\ker L$ . By linearity

$L(\alpha x) = \alpha L(x)=\alpha 0_W=0_W$ .

Then, $\alpha x\in\ker L$ .

Third. Let us prove that $y+ x\in\ker L$ . Again, by linearity

$L(x+y)=L(x)+L(y) = 0_W + 0_W=0_W$ .

And the statement readily follows.

b) Assume that $u$ and $v$ are in range of $L$ . Then, there exist $x,y\in V$ such that $L(x)=u$ and $L(y)=v$ .

First. Let us prove that range of $L$ is not empty. This is easy because $L(0_V)=0_W$ , by linearity.

Second. Let us prove that $\alpha u$ is on the range of $L$ .

$\alpha u = \alpha L(x) = L(\alpha x) = L(z)$ .

Then, there exist an element $z\in V$ such that $L(z)=\alpha u$ . Thus $\alpha u$ is in the range of $L$ .

Third. Let us prove that $u+v$ is in the range of $L$ .

$u+v = L(x)+L(y) = L(x+y)=L(z)$ .

Then, there exist an element $z\in V$ such that $L(z)= u +v$ . Thus $u +v$ is in the range of $L$ .

Notice that in this second part of the problem we used the linearity in the reverse order, compared with the first part of the exercise.

Step-by-step explanation:

6 0

3 years ago

Find the length of each side

Olin [163]

The triangle is equilateral, so all sides are equal.

4x = 3x + 2

x = 2

4x = 8

All sides measure 8 units.

5 0

3 years ago

In parallelogram ABCD, D is a right angle. Is ABCD a rectangle?

Ierofanga [76]

Answer:Yes

Step-by-step explanation:

Because if the parallelogram has an right angle , the opposite angle will also be an right angle.So, in conclusion parallelogram ABCD is a rectangle.

7 0

3 years ago

Read 2 more answers

Use the properties of exponents to write an equivalent expression.

Vladimir [108]

$\frac{ {12}^{6} }{ {12}^{2} }$
Here you subtract the exponent from the other
$\frac{ {12}^{6} }{ {12}^{2} } = {12}^{4}$

For the second one you multiply the exponents as so
$3 \times 5 = 15$
${ ({10}^{3} )}^{5} = {10}^{15}$

6 0

4 years ago

Plzzzz help. Wrong answers will be reported and giving a brainlist.

zysi [14]

It’s A) 24, this is your answer

5 0

3 years ago

Read 2 more answers