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Alchen [17]
2 years ago
15

What mistake did he make ?! I need everybody Anwser

Mathematics
1 answer:
Alla [95]2 years ago
3 0

Answer:

he subtracted the wrong coordinates to find the horizontal leg

Step-by-step explanation:

It should be 4-(-3) but he labeled 4-(-1)

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Find the value of x that will make A||B
olya-2409 [2.1K]

Answer:

7

Step-by-step explanation:

Alternate interior angles must be congruent.

3x - 2 = 2x + 5

x = 7

5 0
3 years ago
Simply and write in standard form. Then classify the polynomial by degree and number of terms (5x^3+3x^2-7x+10)-(3x^3-x^2+4x-1)
Leto [7]

Answer: standard form-2x^3+3x^2-11x+11



7 0
3 years ago
Which of the following values are solutions to the inequality x-8< -2?
avanturin [10]

Answer:

r=8 is a solution. Explanation: To tell whether the given value is a solution to the inequality, we have to solve the inequality. r−3≤9

r=8 is a solution. Explanation: To tell whether the given value is a solution to the inequality, we have to solve the inequality. r−3≤9 Add 3 ... More

Step-by-step explanation:

r=8 is a solution. Explanation: To tell whether the given value is a solution to the inequality, we have to solve the inequality. r−3≤9

r=8 is a solution. Explanation: To tell whether the given value is a solution to the inequality, we have to solve the inequality. r−3≤9 Add 3 ... Morep

5 0
3 years ago
Which of the following expressions is equal to 2x^(2)+8?
dusya [7]

Answer:

The expression equal to 2x^(2)+8 is:

First option (2x-4i)(x+2i)


Step-by-step explanation:

If we multiply

(2x-4i)(x+2i)=(2x)(x)+(2x)(2i)-(4i)(x)-4i(2i)

(2x-4i)(x+2i)=2x^(1+1)+4xi-4xi-8i^(1+1)

Simplifying:

(2x-4i)(x+2i)=2x^2-8i^2

and i^2=-1, then:

(2x-4i)(x+2i)=2x^2-8(-1)

Multiplying:

(2x-4i)(x+2i)=2x^2+8

4 0
4 years ago
Suppose u and v are functions of x that are differentiable at x=0 and that u(0)=4, u′(0)=7, v(0)=2 and v′(0)=1. Find the values
Leona [35]

Answer with Step-by-step explanation:

We are given that u and v are functions of x and both are differentiable at x=0

u(0)=4,u'(0)=7,v(0)=2,v'(0)=1

a.We have to find the values of \frac{d(uv)}{dx}

\frac{d(u\cdot v)}{dx}=u'v+uv'

Using this formula

Then , we get

[\frac{d(uv)}{dx}]_{x=0}=u'(0)v(0)+u(0)v'(0)=7(2)+4(1)=14+4=18

[\frac{d(uv)}{dx}]_{x=0}=18

b.\frac{d(u/v)}{dx}=\frac{u'v-uv'}{v^2}

[\frac{d(u/v)}{dx}]_{x=0}=\frac{u'(0)v(0)-u(0)v'(0)}{v^2(0)}=\frac{7(2)-4(1)}{2^2}=\frac{14-4}{4}=\frac{10}{4}=\frac{5}{2}

[\frac{d(u/v)}{dx}]_{x=0}=\frac{5}{2}

c.

[\frac{d(v/u)}{dx}]_{x=0}=\frac{v'(0)u(0)-v(0)u'(0)}{u^2(0)}=\frac{1(4)-7(2)}{4^2}

[\frac{d(v/u)}{dx}]_{x=0}=\frac{-10}{16}=\frac{-5}{8}

d.\frac{d(-6v-9u)}{dx}=-6v'-9u'

[\frac{d(-6v-9u)}{dx}]_{x=0}=-6v'(0)-9u'(0)=-6(1)-9(7)=-6-63=-69

[\frac{d(-6v-9u)}{dx}]_{x=0}=-69

3 0
3 years ago
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