Answer:
1. b
2. I'm not sure about this one
Step-by-step explanation:
Answer:
0.28cm/min
Step-by-step explanation:
Given the horizontal trough whose ends are isosceles trapezoid
Volume of the Trough =Base Area X Height
=Area of the Trapezoid X Height of the Trough (H)
The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)
The Volume of water in the trough at any time


=8h(8+2x)
V=64h+16hx
We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles
x/h=1/4
4x=h
x=h/4
Substituting x=h/4 into the Volume, V


h=3m,
dV/dt=25cm/min=0.25 m/min

=0.002841m/min =0.28cm/min
The rate is the water being drawn from the trough is 0.28cm/min.
Answer:
It's A.
Step-by-step explanation:
For every value of x there is one value of y - we can draw a vertical line through any value of x and it will pass through only one value of y.
Therefore it is a one-to-one function.
This is the correct answer try it....
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