15y+14=10y+12
15y-10y=12-14
5y= -2
y= -2/5
Answer:
domain: (-∞ , ∞) ; range: f(x) ≥ 3
Step-by-step explanation:
domain: (-∞ , ∞) ; range: f(x) ≥ 3
Minimum required sample size for a desired margin of error and confidence level when it is a proportion problem: n = (z2÷margin of error2)*p-hat*q-hat
The maximum value of p-hat*q-hat occurs where p-hat = .5 (found by taking the derivative of (p-hat)*(1-p-hat) and setting it equal to 0 to find the maximum. n = ( 2.5762( for 99% confidence interval)÷.0482 )*.5*.5 = 720.028 or 721
Answer:
see explanation
Step-by-step explanation:
Using proportion to find the teachers required x, then
= 
( cross- multiply )
221x = 3536 ( divide both sides by 221 )
x = 16
The number of teachers required this year is 16
