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d1i1m1o1n [39]
2 years ago
9

Given: AC and BD are parallel. BX and CY are parallel. AX = DY. Prove: AYC is congruent to DXB

Mathematics
1 answer:
ehidna [41]2 years ago
8 0

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. Using the ASA congruency the triangles are congruent.

<h3>What is a triangle?</h3>

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The sum of all the angles of a triangle is always equal to 180°.

For the two of the given triangles ΔACY and ΔDXB,

  • ∠A = ∠D {Alternate Interior Angles}
  • ∠DXB = ∠ACY {Alternate Interior Angles}
  • AY = YD ⇒ (AX + XY) = (DY + XY) {Given AX=DY}

Since the measure of the two angles and one side of the two triangles are equal, therefore, using the ASA congruency the triangles are congruent.

Learn more about Triangle:

brainly.com/question/2773823

#SPJ1

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