F(x) = 11x² + 5x
f'(x) = 22x + 5
Hence,
f'(9) = (22 * 9) + 5 = 198 + 5 = 203
<u>Part 1)</u> A 20° sector in a circle has an area of 21.5π yd².
What is the area of the circle?
we know that
the area of a circle represent a sector of
degrees
so by proportion
therefore
<u>the answer part 1) is</u>
The area of the circle is 
<u>Part 2)</u> What is the area of a sector with a central angle of 3π/5 radians and a diameter of 21.2 cm?
we know that
the area of the circle is equal to

where
r is the radius of the circle
in this problem we have

<u>Find the area of the circle</u>



<u>Find the area of the sector</u>
we know that the area of the circle represent a sector of
radians
by proportion
therefore
<u>the answer part 2) is</u>
the area of the sector is

Hey there!
1. The graph was flipped vertically and now opens downward.
We know this because there is a negative sign in front of the equation:
2. The graph was moved 3 units to the left.
We know this because there is 3 added to x inside of the parenthesis. Remember, inside (parenthesis) is opposite and acts on x, outside (parenthesis) is same and acts on y.
3. The graph was moved 5 units up.
We know this because there is 5 added at the end of the equation. It acts on y because it is outside of the parenthesis.

Hope this helps!
The correct answer should be steeper
Answer:
15cm^2
Step-by-step explanation:
it is basic math to me.