Question

Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following probability, given the number of trials and the probability of obtaining a success. Round your answer to four decimal places.
P(X<5), n=6, p=0.3

Answer 1

The required probability of success is given by 0.98906500

Assume the random variable X has a binomial distribution with the given probability of obtaining a success.
P(X<5), n=6, p=0.3

What is binomial distribution?

In binomial distribution for number trials we are investigating the probability of getting a success remain the same.

n = number of trails,
p = probability of success
x = the number of success

p(x<5) = P(x=0)+ p(x=1) + p(x=2)+p(x=3)+p(x=4)

= $\binom{6}{0}(0.3)^0(1-0.3)^6+\binom{6}{1}(0.3)^1(1-0.3)^5+\binom{6}{2}(0.3)^2(1-0.3)^4+\binom{6}{3}(0.3)^3(1-0.3)^3+\binom{6}{4}(0.3)^4(1-0.3)^2$

p(x<5) = 0.98906500

Thus the required  probability of success is given by 0.98906500

Learn more about Binomial distribution here:
brainly.com/question/14565246

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