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Trava [24]
2 years ago
7

Which of the following is true?

Mathematics
2 answers:
Andrei [34K]2 years ago
8 0

Answer:

RT is an altitude of GRS

Step-by-step explanation:

An altitude is an angle that shoots through the tip of a triangle. RT and QRS share that.

aleksandrvk [35]2 years ago
7 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The Correct statement is :

  • RT is an altitude of Triangle QRS
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What is the sum of 4/10 + 55/100
neonofarm [45]
4/10 = 40/100

40/100 + 55/100 = 95/100

95/100 is your answer

simplest form: 19/20

hope this helps
4 0
3 years ago
Read 2 more answers
And please explain it?
Brums [2.3K]
You probably jsut need to use law of cosines in order to solve for angle A

c^2 = a^2+b^2 -2ab \cos C
or
a^2 = c^2+b^2 -2cb \cos A
4 0
3 years ago
Need help with this question, thank you in advance!
blondinia [14]

Answer:

arc RP = 84 degrees

Step-by-step explanation:

If the angle NPQ is 102 degrees, we can find the angle NPM:

NPM + NPQ = 180

NPM + 102 = 180

NPM = 78 degrees.

Now, with the triangle NPM, we can find the angle MNP:

60 + 78 + MNP = 180

MNP = 180 - 60 - 78 = 42 degrees

The angle MNP is inscribed in the circle, and is related to the arc RP:

arc RP = 2 * MNP

arc RP = 2 * 42 = 84 degrees

3 0
3 years ago
The area of a room is 600 square feet. The length is (x+2) feet and the width is (x+3) feet. Find the dimensions of the room
m_a_m_a [10]
Create an equation using the formula for area of a rectangle; area = width * length
(X + 2)(x + 3) = 600
Multiply the dimensions.
X^2 + 3x + 2x +6 = 600, or simplified x^2 +5x + 6 = 600.
Subtract 600 to get the following:
X^2 + 5x - 594 = 0
Factor by x:
(X - 22)(x + 27) = 0
Solve for x
X - 22 = 0
X = 22.
Use the POSITIVE VALUE of x as you can’t have a negative area for a room.
Then substitute 22 for x to get the dimensions
(22+ 2) or 24 for length and (22+3) or 25 for width.
6 0
3 years ago
What is the measure of the largest angle of a triangle whose measures are in the ratio 2:3:4
malfutka [58]
2x+3x+4x=180
9x=180
x=20
6 0
3 years ago
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