Answer:
(a)2(89x+84)
(b)
Step-by-step explanation:
The dimensions of the larger rectangular field are:
- Length=5x + 12; Width
= 9x + 14.
The dimensions of the smaller rectangular soccer field are:
(a)Area of the part of the field that is outside the soccer field
=Area of the larger rectangular field - Area of the Soccer Field
=(5x+12)(9x+14)-5x(9x)
=(5x)(9x)+70x+108x+168-5x(9x)
=178x+168
=2(89x+84)
(b)Radius of the Semicircular Fountain =2x
From Part (a),
Area of the larger rectangular field - Area of the Soccer Field=178x+168
Area of the Semicircular Fountain =
Area of the Field that does not include the soccer field or the fountain.
=Area of the larger rectangular field - Area of the Soccer Field-Area of the Semicircular Fountain
Answer:
60
Step-by-step explanation:
Answer:
In the pictures linked.
Step-by-step explanation:
The pictures I linked have the answers. Brainly wouldn't let me submit it because I apparently used bad words.
There would be 3 and 1/2 pounds left.
2/3 x 2 = 4/6
5/6
5/6 + 4/6 = 6/6 (1) and 3/6 (1/2)
The functions which are even are symmetric to y-axis. By even functions, it means that f(x) = f(x) for all the domain values. Thus even functions for example, x^2, 1+x^2, cosx, x^4 all follow the conditions i.e. f(x) = f(x) and thus they are symmterical to y-axis.