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stich3 [128]
2 years ago
6

- 10

Mathematics
1 answer:
e-lub [12.9K]2 years ago
7 0

Answer:

  1. HDUEHD ehvd to be a great day of school and I have a great day of school and
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Can someone help me with this math question & show steps ?
forsale [732]

a xuz if u work it out ull get a

7 0
4 years ago
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Find the value of<br> 10!<br> (10-3)<br> A. 70<br> B. 120<br> O C. 5040<br> O D. 720
GarryVolchara [31]

Answer:

The answer is option D.

Step-by-step explanation:

\frac{10!}{(10 - 3) ! }  =  \frac{10!}{7!}  =  \frac{3628800}{5040}  = 720

Hope this helps you

8 0
3 years ago
Which equation illustrates the division property of equality? PLEASE HELP ME!!
Mekhanik [1.2K]
C does.  8f = 40   divide both sides by 8 to get f=5
8 0
3 years ago
Is the difderence of 1.48-0.25 less than or greater than one? Explain
luda_lava [24]
Greater than 1.Because 1.25-0.25=1.23.That's it.
6 0
4 years ago
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From the given sides of 16, 14, and 21, determine what type of triangle it will form (right, acute, obtuse, none).
Komok [63]

Answer:

It is an acute triangle.

Step-by-step explanation:

It would be much easier for you to see where I'm getting at if you draw a diagram.

Assume this triangle is labelled ABC where a = 14, b = 21, and c = 16.

cos A = (16^2 + 21^2 - 14^2)/(2(16)(21))

∠A = cos^-1(0.82291...)

∠A ≅ 34.6°

cos B = 16^2 + 14^2 - 21^2)/(2(16)(14))

∠B = cos^-1(0.024...)

∠B ≅ 56.8°

∠C = 180 - (∠A + ∠B)

∠C ≅ 56.8°

Since there is no right-angle nor is there an obtuse angle,

Therefore the triangle is an acute triangle.

4 0
3 years ago
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