the answer to your question is:
D (2, -6)
i hope this was helpful ;)
Answer:
-168
Step-by-step explanation:
14(5−11)(2)
=(14)(−6)(2)
=(−84)(2)
=−168
Plug the number for the x value and then solve the equation.
Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]
the area of each trapezoid is (v(t1)+v(t2))/2 times width
for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8
2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24
3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75
4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7
add them all up
0.8+2.24+1.75+0.7=5.49
5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters
This might look hard at first, but if you break it down into parts, it will be much easier. With that said, start with what you know. You see that the word problem says "the difference of y and 9", which means that you have to stubtract them. So, part of the equation is going to be y - 9. Now to look at the rest of the word problem. It says to divide by 3, so now you have to take what you have so far and divide that by 3. This means that you are going to have to divide the y - 9 by 3.
Your answer should be:
y - 9 / 3
***** Note: The slash means division. *************************************
