Question

After grabbing some food from the cafeteria, Ray trips causing his food to go up in the air before hitting the ground. The parabolic path of his food tray can be modeled by the function ℎ() = − 0. 2 , where h is 2 + 0. 4 + 1. 6 the height in meters after t seconds. a)
What is the maximum height of the tray?

If Ray manages to catch the tray at the same height from which the tray flew out of his hands, how long is it in the air?

Answer 1

The maximum height of the tray is 1.8 meters and the tray is in the air for 2 seconds

The maximum height of the tray

The distorted information (i.e. the function) in the question is:

h(t) = -0.2t^2 + 0.4t + 1.6

Differentiate the function

h'(t) = -0.4t + 0.4

Set to 0

-0.4t + 0.4 = 0

Subtract 0.4 from both sides

-0.4t = -0.4

Divide by -0.4

t = 1

Substitute t = 1 in h(t) = -0.2t^2 + 0.4t + 1.6

h(1) = -0.2(1)^2 + 0.4(1) + 1.6

Evaluate

h(1) = 1.8

Hence, the maximum height of the tray is 1.8 meters

Time spent in the air

In (a), we have:

t = 1

This represents the time to reach the maximum height.

The time spent in the air is:

T = 2t

This gives

T = 2 * 1

T = 2

Hence, the tray is in the air for 2 seconds

Read more about quadratic functions at:

brainly.com/question/11535666

#SPJ1