Answer:
she/se jajdjgdgmggdukhmijauuuu
Step-by-step explanation:
jkiek3ke
Answer:
12.35 should be the 10th term sorry if im wrong tho
Step-by-step explanation:
Good afternoon,
x= first odd integer
x+2 = second odd integer
x+4= third intenger
The sum of the trhree integer is 195, so:
x + (x+2) + (x+4) = 195
3x = 195 - 4 - 2
3x=189
x= 63
Then the Answer is: 63, 65 and 67
Answer: The numbers are: " 21 " and " 105 " .
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Explanation:
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Let "x" be the "one positive number:
Let "y" be the "[an]othyer number".
x = 1/5 (y)
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Given that the difference of the two number is "84" ; and that "x" is (1/5) of "y" ; we determine that "x" is smaller than "y".
So, y − x = 84 .
Add "x" to each side of this equation; to solve for "y" in terms of "x" ;
y − x + x = 84 + x ;
y = 84 + x ;
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So, we have:
x = (1/5) y ;
and: y = 84 + x ;
Substitute "(1/5)y" for "x" ; in "y = 84 + x " ; to solve for "y" ;
y = 84 + [ (1/5)y ]
Subtract " [ (1/5)y ] " from EACH SIDE of the equation ;
y − [ (1/5)y ] = 84 + [ (1/5)y ] − [ (1/5)y ] ;
to get:
[ (4/5)y ] = 84 ;
↔ (4y) / 5 = 84 ;
→ 4y = 5 * 84 ;
Divide EACH SIDE of the equation by "4" ;
to isolate "y" on one side of the equation; and to solve for "y" ;
4y / 4 = (5 * 84) / 4 ;
y = 5 * (84/4) = 5 * 21 = 105 .
y = 105 .
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Now, plug "105" for "y" into:
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Either:
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x = (1/5) y ;
OR:
y = 84 + x ;
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to solve for "x" ;
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Let us do so in BOTH equations; to see if we get the same value for "x" ; which is a method to "double check" our answer ;
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Start with:
x = (1/5)y
→ (1/5)*(105) = 105 / 5 = 21 ; x = 21 ;
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So, x = 21; y = 105 .
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Now, let us see if this values hold true in the other equation:
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y = 84 + x ;
105 = ? 84 + 21 ?
105 = ? 105 ? Yes!
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The numbers are: " 21 " and "105 " .
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Answer:
The value of x is 12.
Step-by-step explanation:
In order to find the value of x, we first need to find the scale factor. We can find this by dividing any side of the larger triangle with the corresponding part of the smaller triangle.
28/7 = 4
This means everything in the larger triangle is 4 times as great as the smaller triangle. Knowing this, we can set the larger hypotenuse equal to 4 times the smaller.
6x + 28 = 4(25)
6x + 28 = 100
6x = 72
x = 12