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1 year ago

What does it mean for an event to be unusual? why should the cutoff for identifying unusual events not always be 0. 05?.

1 answer:

4 0

An unusual event is an occurrence that has a low probability of happening. The cutoff for identifying unusual events not always be 0.05, because it is not always a good idea to utilize the same cutoff to spot unexpected occurrences.

<h3>What is an unusual event?</h3>

An unusual event is an occurrence that has a low probability of happening.

If an event is improbable, its likelihood is zero. If an occurrence is unavoidable, its probability is one.

The probability of an event happening increases as it gets closer to 1. An occurrence that has a probability of 0.375, for instance, is more likely to happen than one with a probability of 0.125.

The less likely an event is to occur, the closer the probability is to 0. An unusual event is what this kind of event falls under. A probability of 5%, or 0.05, is typically regarded as unusual event.

Learn more about unusual events here:

brainly.com/question/13839270

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1 year ago

What is a decimal that is equivalent to the expression (2 x 100) + (8 x 10) + (5 x 1) + (6 x 0.01) + (3 x 0.001).

Lana71 [14]

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285.061

Step-by-step explanation:

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2 years ago

36 out of 100 randomly selected taxpayers knew about tax incentives for installing energy-saving furnaces. Find a 90% confidence

tresset_1 [31]

Answer:

The 90% confidence interval for the population proportion who knew about the incentives is (0.28, 0.44).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 100, \pi = \frac{36}{60} = 0.6$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 - 1.645\sqrt{\frac{0.36*0.64}{100}} = 0.28$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 + 1.645\sqrt{\frac{0.36*0.64}{100}} = 0.44$

The 90% confidence interval for the population proportion who knew about the incentives is (0.28, 0.44).

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2 years ago

Multiply / Divide Radical Expressions<br> i need help please.

slava [35]

Answer:

2 with the sqaure root of 12 is = 6.9 simp = 6.9

4 with the sqaure root of 10 is = 12.6 simp= 12.6

sum = 19.5

I hoped this helped! :)

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2 years ago

Solve the system.

anyanavicka [17]

X= -2
Y= -1
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You may use solve this problem by substituting the values as well. If everything goes wrong , go for Cramer’s rule

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2 years ago

What does it mean for an event to be​ unusual? why should the cutoff for identifying unusual events not always be​ 0. 05?.

What does it mean for an event to be unusual? why should the cutoff for identifying unusual events not always be 0. 05?.